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aev [14]
3 years ago
14

Is 3 a solution of the inequality for b + 4 < 6?​

Mathematics
2 answers:
Olegator [25]3 years ago
5 0

Answer:

No.

Step-by-step explanation:

b + 4 < 6 \\ b < 6 - 4 \\ b < 2

Or we can substitute b = 3 in the Inequality.

3 + 4 < 6 \\  7 < 6

From solving the Inequality, 3 is greater than 2. Therefore, 3 is not the solution.

From substitution, 7 < 6 is false. Therefore, 3 is not the solution.

GREYUIT [131]3 years ago
4 0

Answer:

No

Step-by-step explanation:

3+4=7

7>6

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what algorithm (rule) will produce the correct result for the sum "a+b" where a and b each represent any rational number.
Leokris [45]

Answer:

To find the sum of  a + b where a and b are rational number.

1. when a and b are natural numbers

just add them . for example a =3, b=8

then ,a + b = 11

2. When a and b  are whole numbers,

simply add them . for example a= 0, b=8

a+ b = 0 + 8= 8

3. When  a and b are integers

for example, a =-1 b=8,

a+ b= -1+ 8 =7,

a=-2, b= -8

a+ b= -2-8=-10

a= -6 , b=2

a+ b= -6 + 2= -4

a= 8, b= -2

a+ b= 8 +(-2) =6

I have written this because Rational number = [Integers{Whole number(Natural number)}]

now when a= Any fraction=\frac{p}{q} and b = Any fraction=\frac{u}{v}

now ,

\frac{p}{q} + \frac{u}{v}

Find L.C.M of q and v

= if q and v are Co-prime , just multiply them to find their  L.C.M.

For example 14,9. LCM=14×9=126

Otherwise, Find factors of q and v . Then take out common factors first and then multiply the remaining with with common factors.For example

q=12 and v=18

12 =2×2×3

18=2×3×3

common factor =2,3

non common=2,3

L.C.M= 2×2×3×3=36

Suppose LCM of q and v = r

then ,\frac{p}{q} + \frac{u}{v}

=\frac{{\frac{r}{q}}\times p+{\frac{r}{v}\times u}}{r}\\

= {{\frac{r}{q}}\times p+{\frac{r}{v}\times u}} = k

then ,

a + b=\frac{k}{r}





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