Charlie run at a speed of 3 yards per second. about how many miles per hour does charlie run?

igor_vitrenko [27]

Well, first, the equation that you are looking for is Y = MX + B. To find B, look at the first dot on the Y-axis. It starts at positive 3, so, you know your equation will end with +3. Next, to find MX, start at the either dot, and find the Rise/Run. In this particular equation, the rise is 1, and, the run is -2, because it's going backwards (negative line). Meaning, the line's equation would be, f( x )= -1/2x + 3.

5 0

3 years ago

Let L: R2 --> R2 be a linear operator.If L((1,2)T) = (-2,3)Tand L((1,-1)T) = (5,2)TFind the value of L((7,5)T

devlian [24]

Answer: L((7,5)T)=(7, 18)T

Step-by-step explanation:

The step by step explanation is given in picture.

3 0

2 years ago

How to find an equation for a line through two given points?

xz_007 [3.2K]

Answer:

The equation of the line is: $y = 0.6x + 0.6$

Step-by-step explanation:

Equation of a line:

The equation of a line has the following format:

$y = mx + b$

In which m is the slope and b is the y-intercept.

Two points:

We have these following two points in this exercise:

x = -6, y = -3, so (-6,-3)

x = 4, y = 3, so (4,3)

Finding the slope:

Given two points, the slope is given by the change in y divided by the change in x.

Change in y: 3 - (-3) = 3 + 3 = 6

Change in x: 4 - (-6) = 4 + 6 = 10

So

$m = \frac{6}{10} = 0.6$

Then

$y = 0.6x + b$

Finding b:

We replace one of the points in the equation to find b. I will use (4,3).

$y = 0.6x + b$

$3 = 0.6*4 + b$

$2.4 + b = 3$

$b = 0.6$

The equation of the line is: $y = 0.6x + 0.6$

4 0

2 years ago

Find the domain of the graphed function. please help

Anettt [7]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

The Correct choice is :

C.) x > 0

7 0

2 years ago

2 . 2 12n = 42 NEED HELP ASAP⬆️

Anni [7]

Answer:

6

—————

n + 8

Step-by-step explanation:

Step by Step Solution:

More Icon

STEP

1

:

Equation at the end of step 1

((12•(n3))-(24•(n2))) (12n-42)

—————————————————————•———————————————————

(((4•(n2))-22n)+28) ((6•(n3))+(24•3n2))

STEP

2

:

Equation at the end of step

2

:

((12•(n3))-(24•(n2))) (12n-42)

—————————————————————•——————————————————

(((4•(n2))-22n)+28) ((2•3n3)+(24•3n2))

STEP

3

:

12n - 42

Simplify ——————————

6n3 + 48n2

STEP

4

:

Pulling out like terms

4.1 Pull out like factors :

12n - 42 = 6 • (2n - 7)

STEP

5

:

Pulling out like terms

5.1 Pull out like factors :

6n3 + 48n2 = 6n2 • (n + 8)

Equation at the end of step

5

:

((12•(n3))-(24•(n2))) (2n-7)

—————————————————————•————————

(((4•(n2))-22n)+28) n2•(n+8)

STEP

6

:

Equation at the end of step

6

:

((12•(n3))-(24•(n2))) (2n-7)

—————————————————————•————————

((22n2-22n)+28) n2•(n+8)

STEP

7

:

Equation at the end of step

7

:

((12•(n3))-(23•3n2)) (2n-7)

————————————————————•————————

(4n2-22n+28) n2•(n+8)

STEP

8

:

Equation at the end of step

8

:

((22•3n3) - (23•3n2)) (2n - 7)

————————————————————— • ————————————

(4n2 - 22n + 28) n2 • (n + 8)

STEP

9

:

12n3 - 24n2

Simplify ——————————————

4n2 - 22n + 28

STEP

10

:

Pulling out like terms

10.1 Pull out like factors :

12n3 - 24n2 = 12n2 • (n - 2)

STEP

11

:

Pulling out like terms

11.1 Pull out like factors :

4n2 - 22n + 28 = 2 • (2n2 - 11n + 14)

Trying to factor by splitting the middle term

11.2 Factoring 2n2 - 11n + 14

The first term is, 2n2 its coefficient is 2 .

The middle term is, -11n its coefficient is -11 .

The last term, "the constant", is +14

Step-1 : Multiply the coefficient of the first term by the constant 2 • 14 = 28

Step-2 : Find two factors of 28 whose sum equals the coefficient of the middle term, which is -11 .

-28 + -1 = -29

-14 + -2 = -16

-7 + -4 = -11 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -7 and -4

2n2 - 7n - 4n - 14

Step-4 : Add up the first 2 terms, pulling out like factors :

n • (2n-7)

Add up the last 2 terms, pulling out common factors :

2 • (2n-7)

Step-5 : Add up the four terms of step 4 :

(n-2) • (2n-7)

Which is the desired factorization

Canceling Out :

11.3 Cancel out (n-2) which appears on both sides of the fraction line.

Equation at the end of step

11

:

6n2 (2n - 7)

—————— • ————————————

2n - 7 n2 • (n + 8)

STEP

12

:

Canceling Out

12.1 Cancel out (2n-7) which appears on both sides of the fraction line.

Canceling Out :

12.2 Canceling out n2 as it appears on both sides of the fraction line

Final result :

6

—————

n + 8

8 0

3 years ago