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sveticcg [70]
2 years ago
10

Triangle IJK, with vertices I(-9,-8), J(-5,-6), and K(-7,-3), is drawn on the coordinate grid below.

Mathematics
1 answer:
Ilia_Sergeevich [38]2 years ago
5 0

Answer:

Area= 8

Step-by-step explanation:

Given

I = (-9,-8)

J = (-5,-6)

K = (-7,-3)

The complete part of the question is to calculate the area of IJK

The area is calculated using:

Area = \frac{1}{2}|x_1y_2 - x_2y_1 + x_2y_3 - x_3y_2 + x_3y_1 - x_1y_3 |

Where:

I = (-9,-8) --- (x_1,y_1)

J = (-5,-6) --- (x_2,y_2)

K = (-7,-3) --- (x_3,y_3)

So, we have:

Area = \frac{1}{2}|(-9*-6) - (-5*-8) + (-5*-3) - (-7*-6) + (-7*-8) - (-9*-3) |

Solve the brackets

Area = \frac{1}{2}|54 - 40 + 15- 42 + 56 - 27 |

Area = \frac{1}{2}|16|

The absolute value of 16 is 16

So:

Area = \frac{1}{2} * 16

Area= 8

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