Question

Triangle IJK, with vertices I(-9,-8), J(-5,-6), and K(-7,-3), is drawn on the coordinate grid below.

Answer 1

Answer:

$Area= 8$

Step-by-step explanation:

Given

$I = (-9,-8)$

$J = (-5,-6)$

$K = (-7,-3)$

The complete part of the question is to calculate the area of IJK

The area is calculated using:

$Area = \frac{1}{2}|x_1y_2 - x_2y_1 + x_2y_3 - x_3y_2 + x_3y_1 - x_1y_3 |$

Where:

$I = (-9,-8)$ --- $(x_1,y_1)$

$J = (-5,-6)$ --- $(x_2,y_2)$

$K = (-7,-3)$ --- $(x_3,y_3)$

So, we have:

$Area = \frac{1}{2}|(-9*-6) - (-5*-8) + (-5*-3) - (-7*-6) + (-7*-8) - (-9*-3) |$

Solve the brackets

$Area = \frac{1}{2}|54 - 40 + 15- 42 + 56 - 27 |$

$Area = \frac{1}{2}|16|$

The absolute value of 16 is 16

So:

$Area = \frac{1}{2} * 16$

$Area= 8$