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Mathematics

1 answer:

Marysya12 [62]3 years ago

4 0

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$4z + 2 = 10z - 1$

Add sides 1

$4z + 2 + 1 = 10z - 1 + 1$

$4z + 3 = 10z$

Subtract sides 4z

$- 4z + 4z + 3 = - 4z + 10z$

$3 = 6z$

$6z = 3$

Divide sides by 6

$\frac{6z}{6} = \frac{3}{6} \\$

$z = \frac{1}{2} \\$

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$3y = y + 3$

Subtract sides y

$- y + 3y = - y + y + 3$

$2y = 3$

Divide sides by 2

$\frac{2y}{2} = \frac{3}{2} \\$

$y = \frac{3}{2} \\$

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Thus the correct answer is :

$a) \: y = \frac{3}{2} \: , \: z = \frac{1}{2} \\$

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Step-by-step explanation:

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