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SSSSS [86.1K]
3 years ago
10

Can someone help? Thanks! :)

Mathematics
1 answer:
sukhopar [10]3 years ago
5 0

Answer:

<em>The second figure ( rectangle ) has a longer length of it's diagonal comparative to the first figure ( square )</em>

Step-by-step explanation:

We can't confirm the length of these diagonals based on the appearance of the figure, so let us apply Pythagorean Theorem;

This diagonal divides each figure ( square + rectangle ) into two congruent, right angle triangles ⇒ from which we may apply Pythagorean Theorem, where the diagonal acts as the hypotenuse;

5^2 + 5^2 = x^2 ⇒ x is the length of the diagonal,

25 + 25 = x^2,

x^2 = 50,

x = √50

Now the same procedure can be applied to this other quadrilateral;

3^2 + 7^2 = x^2 ⇒ x is the length of the diagonal,

9 + 49 = x^2,

x^2 = 58,

x = √58

<em>Therefore the second figure ( rectangle ) has a longer length of it's diagonal comparative to the first figure ( square )</em>

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Step-by-step explanation:

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Solve this application problem using a system of equations: Dan and June mix two kinds of feed for pedigreed dogs. They wish to
wlad13 [49]

Answer:

50 pounds

Step-by-step explanation:

Dan and june mix two kind of feed for pedigreed dogs

Feed A worth is $0.26 per pound

Feed B worth is $0.40 per pound

Let x represent the cheaper amount of feed and y the costlier type of feed

x+y= 70..........equation 1

0.26x + 0.40y= 0.30×70

0.26x + 0.40y= 21.........equation 2

From equation 1

x + y= 70

x= 70-y

Substitutes 70-y for x in equation 2

0.26(70-y) + 0.40y= 21

18.2-0.26y+0.40y= 21

18.2+0.14y= 21

0.14y= 21-18.2

0.14y= 2.8

Divide both sides by the coefficient of y which is 0.14

0.14y/0.14= 2.8/0.14

y= 20

Substitute 20 for y in equation 1

x + y= 70

x + 20= 70

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4 0
4 years ago
The mean amount spent by a family of four on food per month is $500 with a standard deviation of $75. Assuming that the food cos
JulijaS [17]

Answer:

The probability that a family spends less than $410 per month

P( X < 410) = 0.1151

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given mean of the population = 500 </em>

<em>Given standard deviation of the Population = 75</em>

Let 'X' be the variable in normal distribution

      Z = \frac{x-mean}{S.D}

<em>Given X = $410</em>

<em></em>Z = \frac{410-500}{75} = - 1.2<em></em>

<u><em>Step(ii):-</em></u>

The probability that a family spends less than $410 per month

P( X < 410) = P( Z < - 1.2 )

                  =  0.5 - A( -1.2)

                 = 0.5 - A(1.2)

                = 0.5 - 0.3849  ( ∵from normal table)

                = 0.1151

<u>Final answer:-</u>

The probability that a family spends less than $410 per month

P( X < 410) = 0.1151

6 0
3 years ago
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