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SSSSS [86.1K]
3 years ago
10

Can someone help? Thanks! :)

Mathematics
1 answer:
sukhopar [10]3 years ago
5 0

Answer:

<em>The second figure ( rectangle ) has a longer length of it's diagonal comparative to the first figure ( square )</em>

Step-by-step explanation:

We can't confirm the length of these diagonals based on the appearance of the figure, so let us apply Pythagorean Theorem;

This diagonal divides each figure ( square + rectangle ) into two congruent, right angle triangles ⇒ from which we may apply Pythagorean Theorem, where the diagonal acts as the hypotenuse;

5^2 + 5^2 = x^2 ⇒ x is the length of the diagonal,

25 + 25 = x^2,

x^2 = 50,

x = √50

Now the same procedure can be applied to this other quadrilateral;

3^2 + 7^2 = x^2 ⇒ x is the length of the diagonal,

9 + 49 = x^2,

x^2 = 58,

x = √58

<em>Therefore the second figure ( rectangle ) has a longer length of it's diagonal comparative to the first figure ( square )</em>

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