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SSSSS [86.1K]
2 years ago
10

Can someone help? Thanks! :)

Mathematics
1 answer:
sukhopar [10]2 years ago
5 0

Answer:

<em>The second figure ( rectangle ) has a longer length of it's diagonal comparative to the first figure ( square )</em>

Step-by-step explanation:

We can't confirm the length of these diagonals based on the appearance of the figure, so let us apply Pythagorean Theorem;

This diagonal divides each figure ( square + rectangle ) into two congruent, right angle triangles ⇒ from which we may apply Pythagorean Theorem, where the diagonal acts as the hypotenuse;

5^2 + 5^2 = x^2 ⇒ x is the length of the diagonal,

25 + 25 = x^2,

x^2 = 50,

x = √50

Now the same procedure can be applied to this other quadrilateral;

3^2 + 7^2 = x^2 ⇒ x is the length of the diagonal,

9 + 49 = x^2,

x^2 = 58,

x = √58

<em>Therefore the second figure ( rectangle ) has a longer length of it's diagonal comparative to the first figure ( square )</em>

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Nikitich [7]

The acceleration of the particle is given by the formula mentioned below:

a=\frac{d^2s}{dt^2}

Differentiate the position vector with respect to t.

\begin{gathered} \frac{ds(t)}{dt}=\frac{d}{dt}\sqrt[]{\mleft(t^3+1\mright)} \\ =-\frac{1}{2}(t^3+1)^{-\frac{1}{2}}\times3t^2 \\ =\frac{3}{2}\frac{t^2}{\sqrt{(t^3+1)}} \end{gathered}

Differentiate both sides of the obtained equation with respect to t.

\begin{gathered} \frac{d^2s(t)}{dx^2}=\frac{3}{2}(\frac{2t}{\sqrt[]{(t^3+1)}}+t^2(-\frac{3}{2})\times\frac{1}{(t^3+1)^{\frac{3}{2}}}) \\ =\frac{3t}{\sqrt[]{(t^3+1)}}-\frac{9}{4}\frac{t^2}{(t^3+1)^{\frac{3}{2}}} \end{gathered}

Substitute t=2 in the above equation to obtain the acceleration of the particle at 2 seconds.

\begin{gathered} a(t=1)=\frac{3}{\sqrt[]{2}}-\frac{9}{4\times2^{\frac{3}{2}}} \\ =1.32ft/sec^2 \end{gathered}

The initial position is obtained at t=0. Substitute t=0 in the given position function.

\begin{gathered} s(0)=-23\times0+65 \\ =65 \end{gathered}

8 0
1 year ago
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andriy [413]
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3 0
2 years ago
Read 2 more answers
Encontrar el valor d la variable
Yuki888 [10]
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7 0
3 years ago
a bag holds 1200 marbles colored either blue, red, green, or pink. there are 2 more blue than green, 6 more green than red and 6
krek1111 [17]
B = 2 + g . . . (1)
g = 6 + r . . . (2)
r = 6 + p . . . (3)

Putting (3) into (2) gives:
g = 6 + 6 + p = 12 + p . . . (4)
Putting (4) into (1) gives:
b = 2 + 12 + p = 14 + p . . . (5)

b + g + r + p = 1200
2 + g + 6 + r + 6 + p + p = 1200
2 + 12 + p + 6 + 6 + p + 6 + p + p = 1200
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From (5), b = 14 + p = 14 + 292 = 306

Therefore, there are 306 blue mables.
8 0
3 years ago
22. A charter bus company charges a flat fee of $175, plus $2.50 per mile (one-way distance) for a bus. If the band paid exactly
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Answer:

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Step-by-step explanation:

625 - 175= 450

450 divided by 2.50 = 180

7 0
2 years ago
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