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ehidna [41]
3 years ago
6

Interpret the meaning of the point (9, 378).

Mathematics
1 answer:
lions [1.4K]3 years ago
7 0

Answer:

it means the the line falls on 9 on the x-axis

and intersects at 378 on the y-axis

Step-by-step explanation:

hope that helped

You might be interested in
Use Lagrange multipliers to find the maximum and minimum values of (i) f(x,y)-81x^2+y^2 subject to the constraint 4x^2+y^2=9. (i
sp2606 [1]

i. The Lagrangian is

L(x,y,\lambda)=81x^2+y^2+\lambda(4x^2+y^2-9)

with critical points whenever

L_x=162x+8\lambda x=0\implies2x(81+4\lambda)=0\implies x=0\text{ or }\lambda=-\dfrac{81}4

L_y=2y+2\lambda y=0\implies2y(1+\lambda)=0\implies y=0\text{ or }\lambda=-1

L_\lambda=4x^2+y^2-9=0

  • If x=0, then L_\lambda=0\implies y=\pm3.
  • If y=0, then L_\lambda=0\implies x=\pm\dfrac32.
  • Either value of \lambda found above requires that either x=0 or y=0, so we get the same critical points as in the previous two cases.

We have f(0,-3)=9, f(0,3)=9, f\left(-\dfrac32,0\right)=\dfrac{729}4=182.25, and f\left(\dfrac32,0\right)=\dfrac{729}4, so f has a minimum value of 9 and a maximum value of 182.25.

ii. The Lagrangian is

L(x,y,z,\lambda)=y^2-10z+\lambda(x^2+y^2+z^2-36)

with critical points whenever

L_x=2\lambda x=0\implies x=0 (because we assume \lambda\neq0)

L_y=2y+2\lambda y=0\implies 2y(1+\lambda)=0\implies y=0\text{ or }\lambda=-1

L_z=-10+2\lambda z=0\implies z=\dfrac5\lambda

L_\lambda=x^2+y^2+z^2-36=0

  • If x=y=0, then L_\lambda=0\implies z=\pm6.
  • If \lambda=-1, then z=-5, and with x=0 we have L_\lambda=0\implies y=\pm\sqrt{11}.

We have f(0,0,-6)=60, f(0,0,6)=-60, f(0,-\sqrt{11},-5)=61, and f(0,\sqrt{11},-5)=61. So f has a maximum value of 61 and a minimum value of -60.

5 0
3 years ago
Help please :) ill give brainliest to correct answer.
aliina [53]

The answer is Answer:

y = -1 x + 8

8 0
3 years ago
I NEED ASWERS FAST<br> The question is number 5
alekssr [168]

Answer:

<h2>c. 1056</h2>

100% right answer

6 0
2 years ago
How to solve? I prob know it I'm just stressing and panicking from all other stuff I gotta do
Nata [24]
Left one i think thats the one 
8 0
3 years ago
Where am I to put the points? help?
maria [59]

we know that a has to be a number less than 0 and c has to be a number greater than 0. so a has to go before the number 0 and b can go before or after 0, as long as it satisfies the equation

7 0
2 years ago
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