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klio [65]
4 years ago
8

Help I am stuck on this question

Mathematics
1 answer:
zubka84 [21]4 years ago
8 0
Only choices B and C are in the 3rd quadrant. The point B(-4, -1.5) is not inside the circle or the rectangle.

The appropriate choice is ...
  C. (-1.5, -2)
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What is the solution to the system of linear equations? 2x + 3y = 3 3x + 5y = 5 Enter you answer into the boxes.
aleksandr82 [10.1K]

Answer:

x = 0

y = 1

Step-by-step explanation:

2x + 3y = 3               Multiply this equation by 3

3x + 5y = 5               Multiply this equation by 2

3(2x + 3y = 3)

6x + 9y = 9

2(3x + 5y = 5  )

6x + 10y = 10             Notice the xs are the same.

6x + 9y = 9

<u>6x + 10y =10 </u>            Subtract

     - y = - 1                Multiply each side by -1

     y = 1

2x + 3y = 3

2x + 3*1 = 3

2x = 0

x =0

4 0
3 years ago
Find x, please don't put random answers for points
Gala2k [10]

Answer:

The answer will be x=6.07 I believe

Step-by-step explanation:

I hope this Helped

3 0
3 years ago
Read 2 more answers
Explain how to round a number to the nearest ten.
Serhud [2]
After the decimal, the first number is the tenth place, if the second number after the decimal is 5 or bigger then you round up the first number after the decimal. if it’s lower than 5 then you keep the same number
5 0
3 years ago
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Write an equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the gi
dimulka [17.4K]

a parallel line to that equation will have the same exact slope, so

\bf y=\stackrel{\stackrel{m}{\downarrow }}{-3}x+5\impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

then we're really looking for the equation of a line whose slope is -3, and runs through (-5,-8)

\bf (\stackrel{x_1}{-5}~,~\stackrel{y_1}{-8})~\hspace{10em} slope = m\implies -3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-8)=-3[x-(-5)] \\\\\\ y+8=-3(x+5)\implies y+8=-3x-15\implies y=-3x-23

3 0
3 years ago
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A trapezoid is a quadrilateral with one or more pairs of parallel sides.<br> O A. True<br> OB. False
salantis [7]
The answer is B. False
6 0
2 years ago
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