Answer:
The first digit of a two digit number can be any of digits 1 - 9. It cannot be 0 though. Therefore there are 9 possible digits for the first place.
There are 5 possible digits for the second position. The two digit number has to be odd and therefore the final digit must be 1,3,5,7 or 9
Therefore for each and every one of the nine first digits there are 5 digits that the second can be.
Therefore ANSWER = 9 * 5 = 45 possible permutations.
2. The largest two digit number = 99
Subtract 57 and you get 42
ANSWER = 42
The forty two numbers are 58 ,59, 60, 61......98, 99
Answer:
Step-by-step explanation:
do you know the answer
Here is your answer! The coefficient of xy is 6. To solve this problem, you need to multiply your two polynomials together. I used the FOIL Method- multiply the First two, the Outside two, the Inside two, and the Last two. You can see how I did it on the picture attached. Next, the answer that you get as a result from FOILing is your polynomial. If you look at the number before xy, that is the coefficient. A coefficient is a number that is right before and attached to a variable. I hope this helps you! :))
10.1 x 8 - 6 = 80.8 - 6 = 74.8
u just had to substitute the variables
Answer:
The amount of Polonium-210 left in his body after 72 days is 6.937 μg.
Step-by-step explanation:
The decay rate of Polonium-210 is the following:
(1)
Where:
N(t) is the quantity of Po-210 at time t =?
N₀ is the initial quantity of Po-210 = 10 μg
λ is the decay constant
t is the time = 72 d
The decay rate is 0.502%, hence the quantity that still remains in Alexander is 99.498%.
First, we need to find the decay constant:
(2)
Where t(1/2) is the half-life of Po-210 = 138.376 days
By entering equation (2) into (1) we have:
Therefore, the amount of Polonium-210 left in his body after 72 days is 6.937 μg.
I hope it helps you!