Question

If the first term of a sequence is 5 and the tenth term is -58, what is the common difference? -3 -4 -5 -6 -7

Answer 1

Answer:

Common difference of the sequence is -7.

Step-by-step explanation:

Given:

First term a = 5

Tenth term $T_{10}$ = -58

we need to find the common difference d.

Now let the number of terms will be 10 since tenth term is given;

Hence n =10

Now Using Arithmetic Progression formula we get;

$T_n = a+(n-1)d$

Now Substituting the given values in the formula we get;

$T_{10}=5+(10-1)d\\-58 = 5+9d\\-58-5=9d\\-63=9d\\\\-\frac{63}{9}=d\\\\d=-7$

Hence Common difference of the sequence will be -7.