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Stels [109]
3 years ago
13

If x3 = 27, what is the value of x?

Mathematics
1 answer:
ipn [44]3 years ago
8 0

Answer:

The value of x is 3

Step-by-step explanation:

Given:

x^3 = 27

To Find:

x = ?

Solution:

We Know that

a = (a^3)^\frac{1}{3}

a = (a)^\frac{3}{3}

We can write 27 as 3 \times 3 \times 3 = 3^3

Taking cube root on both sides

(x^3)^{\frac{1}{3} }= (3^3)^{\frac{1}{3}}

x^{\frac{3}{3}} = 3^{\frac{3}{3}}

x^1 = 3^1

x = 3

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Let G be a connnectde graph with n vertices and m edges. supposed also that m = n. prove that G contains exactly one cycle
ElenaW [278]

Answer:

Contradiction

Step-by-step explanation:

Suppose that G has more than one cycle and let C be one of the cycles of G, if we remove one of the edges of C from G, then by our supposition the new graph G' would have a cycle. However, the number of edges of G' is equal to m-1=n-1 and G' has the same vertices of G, which means that n is the number of vertices of G. Therefore, the number of edges of G' is equal to the number of vertices of G' minus 1, which tells us that G' is a tree (it has no cycles), and so we get a contradiction.

7 0
3 years ago
What is 21 times 1/3=
tiny-mole [99]

Answer:

7

Step-by-step explanation:

21×1/3

21÷3=7

hope I've helped

4 0
2 years ago
Ms. Lynch has 21 coins in nickels and dimes.
bulgar [2K]

Answer:

Step-by-step explanation:So we know x + y = 21 and 5x +10y = 165 We line them up in columns    x +   y =   21  5x +10y = 165 To eliminate the x variable, I'll multiply every element in the 1st equation by -5. -5x + -5y = -105  5x + 10y =  165 Now we combine (add) the equations, which eliminates x altogether.  5y = 60   ...   y = 12 From there, x + 12 = 21  ...  x = 21-12  ...  x = 9 You should double check.  Do 9 nickles and 12 dimes equal $1.65? A very important thing to remember using this method is to do the same thing to each element in the equation that you change! I hope that helps.

4 0
2 years ago
Helllppp porfavor:,)
tatuchka [14]

Answer:

1. x = 67.5

2. x = 2.5

3. x = 35.2

4. x = 2.0

5. x = 17.0

Step-by-step explanation:

Question 1

The proportion is set up in the form x/9 = 15/2. Multiply both sides by two to get rid of the two in the denominator on the right side. After doing so, multiply by 9 on both sides to get rid of the 9 in the denominator on the left:

2x/9 = 15

2x = 9(15)

Next solve for x:

2x = 135

x = 67.5

Question 2

The proportion is set up in the form 20/8.7 = 5.8/x. Multiply both sides by the second denominator, x, and then both sides by the first, 8.7. This will leave you with the work below:

20x/8.7 = 5.8

20x = 8.7(5.8)

Next, solve for x:

20x = 50.46

x = 2.523

Round to the nearest tenth:

x = 2.5

Question 3

The proportion is set up in the form 5/16 = 11/x. Multiply both sides by the second denominator, x, and then both sides by the first, 16. This will leave you with the work below:

5x/16 = 11

5x = 11(16)

Next, solve for x:

5x = 176

x = 35.2

Question 4

The proportion is set up in the form x/0.06 = 17/0.5. Multiply both sides by the second denominator, 0.5, and then both sides by the first, 0.06. This will leave you with the work below:

0.5x/0.06 = 17

0.5x = 17(0.06)

Next, solve for x:

0.5x = 1.02

x = 2.04

Round to the nearest tenth:

x = 2.0

Question 5

The proportion is set up in the form 29/x = 75/44. Multiply both sides by the second denominator, 44, and then both sides by the first, x. This will leave you with the work below:

29(44)/x = 75

29(44) = 75x

Next, solve for x:

1276 = 75x

x = 17.0133

Round to the nearest tenth:

x = 17.0

7 0
2 years ago
What is the outlier of 29, 2, 28, 30, 26, 31
Vladimir [108]

Answer:

2

Step-by-step explanation:

Given the data : 29, 2, 28, 30, 26, 31

Outlier ;

Lower :Q1 - (1.5 * IQR)

Upper : Q3 + (1.5 * IQR)

Q1 = Lower quartile ; Q3 = upper quartile ; IQR = Interquartile range

Using calculator :

Q1 = 26

Q3 = 30

IQR = (Q3 - Q1) = 30 - 26 = 4

Lower : 26 - (1.5 * 4) = 20

Upper : 30 + (1.5 * 4) = 36

Hence, the number in the given data which falls outside the range is 2

4 0
3 years ago
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