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2 years ago

How many boxes of markers must be sold for the company’s income to equal the cost of production

Mathematics

1 answer:

Margaret [11]2 years ago

6 0

C. 200

They earn $2.50 per box of markers, meaning that to make $500 they have to sell 200. [500/2.5=200]

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Which inequality is true? Use the number line to help.

PolarNik [594]

Answer:

C) -1.5 < -0.5

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3 years ago

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Find the sum of and 6/7 and 2/3 express your answer in lowest terms.

tensa zangetsu [6.8K]

Answer:

1 11/21

Step-by-step explanation:

6/7 + 2/3 = 32/21

32/21 simplified is 1 11/21

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4 years ago

PLEASE HELP ME I DONT UNDERSTAND THIS AT ALL

Delicious77 [7]

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3 years ago

. A right cylindrical drum is to hold 7.35 cubic feet of liquid. Find the dimensions (radius of the base and height) of the drum

Drupady [299]

Answer:

$r=1.05\ \text{ft}$

$h=2.12\ \text{ft}$

$20.91\ \text{ft}^3$

Step-by-step explanation:

r = Radius

h = Height

Volume of cylinder = $7.35\ \text{ft}^3$

$V=\pi r^2h\\\Rightarrow h=\dfrac{V}{\pi r^2}\\\Rightarrow h=\dfrac{7.35}{\pi r^2}$

Surface area is given by

$A=2\pi r^2+2\pi rh\\\Rightarrow A=2\pi r^2+2\pi r\dfrac{7.35}{\pi r^2}\\\Rightarrow A=2\pi r^2+\dfrac{14.7}{r}$

Differentiating with respect to radius we get

$\dfrac{dA}{dr}=4\pi r-\dfrac{14.7}{r^2}$

Equating with zero we get

$0=4\pi r-\dfrac{14.7}{r^2}\\\Rightarrow 4\pi r=\dfrac{14.7}{r^2}\\\Rightarrow r^3=\dfrac{14.7}{4\pi}\\\Rightarrow r=(\dfrac{14.7}{4\pi})^{\dfrac{1}{3}}\\\Rightarrow r=1.05$

$\dfrac{d^2A}{dr^2}=4\pi-2\times \dfrac{14.7}{r^3}\\\Rightarrow \dfrac{d^2A}{dr^2}=4\pi+2\times \dfrac{14.7}{1.05^3}\\\Rightarrow \dfrac{d^2A}{dr^2}=37.96>0$

So, the value of the function is minimum at $r=1.05$

$h=\dfrac{7.35}{\pi r^2}=\dfrac{7.35}{\pi 1.05^2}\\\Rightarrow h=2.12$

So, the radius and height which would minimize the surface area is 1.05 feet and 2.12 feet respectively.

Surface area

$A=2\pi r^2+2\pi rh\\\Rightarrow A=2\pi \times 1.05^2+2\pi 1.05\times 2.12\\\Rightarrow A=20.91\ \text{ft}^3$

The minimum surface area is $20.91\ \text{ft}^3$ .

8 0

3 years ago

Find the minimum cost of producing 50,000 units of a product, where x is the number of units of labor (at $36 per unit) and y is

erastovalidia [21]

Answer:

Step-by-step explanation:

Given problem: C(x,y) = 36x + 48y

constraint: 100x^0.6y^0.4

Using langrange Multiplier,

36 = 0.6(100)x^-0.4y^0.4λ i

48 = 0.4(100)x^0.6y^-0.6λ ii

dividing the equations we have:

x = 2y

substituting into the constraint

p(x,y) = 100 *(2y)^0.6 y^0.4 = 100*2^0.6 *y

5000 = 151.572y

y = 329.876 labor units

x = 659.752 capital units

Minimum cost = 36(659.752) +48(329.876) = $39585.12

6 0

3 years ago