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3 years ago

14

Jacobs sand bucket has a top diameter of 10 inches and a bottom diameter of 7 inches. the bucket is 12 inches tall. What’s the v

olume

1 answer:

Elanso [62]3 years ago

4 0

We know that
The volume of a circular truncated cone=(1/3)*pi*[r1²+r1*r2+r2²]*h
where
r1=7/2-----> 3.5 in
r2=10/2----> 5 in
h=12 in
volume of a circular truncated cone=(1/3)*pi*[3.5²+3.5*5+5²]*12
volume=688 in³

the answer is
688 in³

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40

Step-by-step explanation:

(6 + 2i)(6 - 2i)=40

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A restaurant offers a special pizza with any 4 toppings. If the restaurant has 15 topping from which to choose, how many differe

OlgaM077 [116]

Answer: 1,365 possible special pizzas

Step-by-step explanation:

For the first topping, there are 15 possibilities, for the second topping, there are 14 possibilities, for the third topping, there are 13 possibilities, and for the fourth topping, there are 12 possibilities. This is how you find the number of possible ways.

15 * 14 * 13 * 12 = 32,760

Now, you need to divide that by the number of toppings you are allowed to add each time you add a topping.

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3 years ago

Cho S là ngoại diên của khái niệm con người, p(x,y) = x yêu thương y.

pentagon [3]

Answer:

Step-by-step explanation:

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3 years ago

Pregnant women metabolize some drugs at a slower rate than the rest of the population. The half-life of caffeine is about 4 hour

UkoKoshka [18]

Answer:

Husband:

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Woman:

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

Step-by-step explanation:

The amount of caffeine in the body can be modeled by the following equation:

$C(t) = C(0)e^{rt}$

In which C(t) is the amount of caffeine t hours after 8 am, C(0) is how much coffee they took and r is the rate the the amount of caffeine decreases in their bodies.

110 mg of caffeine at 8 am,

So $C(0) = 110$

Husband

Half life of 4 hours. So

$C(4) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{4r}$

$e^{4r} = 0.5$

Applying ln to both sides

$\ln{e^{4r}} = \ln{0.5}$

$4r = \ln{0.5}$

$r = \frac{\ln{0.5}}{4}$

$r = -0.1733$

So for the husband

$C(t) = 110e^{-0.1733t}$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.1733t}$

$C(11) = 110e^{-0.1733*11} = 16.35$

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Pregnant woman

Half life of 10 hours. So

$C(10) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{10}$

$e^{10r} = 0.5$

Applying ln to both sides

$\ln{e^{10r}} = \ln{0.5}$

$10r = \ln{0.5}$

$r = \frac{\ln{0.5}}{10}$

$r = -0.0693$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.0693t}$

$C(11) = 110e^{-0.0693*11} = 51.33$

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

7 0

4 years ago

Please show your work, tysm :D<br><br> ~giving brainliest!~

N76 [4]

Answer:

. 0625

Step-by-step explanation:

1/2^4

or

1/16

just doing half life

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2 years ago