For this we almost have the following equation:

We must match the equation to zero:

From here, we clear the value of t.
We have then:

We discard the negative root because we are looking for time:
Answer:
it will take him to reach the ground about:

seconds
<span>2 x^2 y^6 z^5
5 x^4 y^5 z^3
---------------
10 ^6 ^11 ^8</span>
The triangle that is formed by AMB is a 45 45 90 triangle, so meaning the legs are equal. so in can be concluded that AD = MD, since M is the midpoint of CD, then CD = 2AD
CD = 2(6) = 12 cm
so the perimeter is of the rectangle ABCD is
P = 2l + 2w
P = 2(6) + 2(12)
P = 12 + 24
P = 26 cm
Answer:
w=3/5 or w=-5
Step-by-step explanation:
5w^2+22w=15
5w^2+22w-15=0 (quadratic equation)
a=5, b=22, c=-15
w1,2 =(-b+-sqrt(b^2-4ac))/2a
w1,2 =(-22+-sqrt(22^2-4*5*(-15))/2*5
w1,2 =(-22+-sqrt(484+300))/10
w1,2=(-22+-sqrt(784))/10
w1,2=(-22+-28)/10
w1=(-22+28)/10, w2=(-22-28)/10
w1=6/10, w2=-50/10
w1=3/5, w2=-5