Answer:
See below
Step-by-step explanation:
5x + y = 9 re-arrange to y = 9-5x
use this value of 'y' in the second equation:
10x - 7(9-5x) = - 18
solve for x = 1
sub in this value of 'x' into one of the equations to compute 'y'
5 (1) + y = 9
y = 4
Multiply the denominators. Way 2: Move decimal points, divide, and place a decimal point in the quotient. Step 1 Write a decimal point and a zero in the dividend. Step 2 Multiply the divisor by a power of 10 to get a whole number.
<span>Answer:
rc length=â«âšr2+(drdθ)2â‹…dθ
for a equation r=θ2,
drdθ=2θ
â´ Arc length=â«âšÎ¸4+4θ2â‹…dθ
by factoring out θ and rewriting a bit,
=â«Î¸âšÎ¸2+4â‹…dθ=12â«(θ2+4)12â‹…2θdθ
by General Power Rule,
=12⋅(θ2+4)3232+k=13(θ2+4)32+k
Let's assume that 0≤θ≤2π
Arc length=â«2Ď€0âšÎ¸4+4θ2â‹…dθ=92.9</span>
Answer:
$53750
Step-by-step explanation:
Sam deposit $12500 every year which grows at a simple interest of 3% and we have to calculate the total sum after 4 years.
If Sam deposit $x with r% simple interest then the principal will grow after 4 years to ![x[1 + \frac{4r}{100}]](https://tex.z-dn.net/?f=x%5B1%20%2B%20%5Cfrac%7B4r%7D%7B100%7D%5D)
Again, for the second year $x investment with r% simple interest will grow to ![x[1 + \frac{3r}{100}]](https://tex.z-dn.net/?f=x%5B1%20%2B%20%5Cfrac%7B3r%7D%7B100%7D%5D)
.
Now, the third year $x investment with r% simple interest will grow to ![x[1 + \frac{2r}{100}]](https://tex.z-dn.net/?f=x%5B1%20%2B%20%5Cfrac%7B2r%7D%7B100%7D%5D)
And finally the fourth year $x investment with r% simple interest will grow to ![x[1 + \frac{r}{100}]](https://tex.z-dn.net/?f=x%5B1%20%2B%20%5Cfrac%7Br%7D%7B100%7D%5D)
Therefore, the total sum becomes
![x[1 + \frac{4r}{100}] + x[1 + \frac{3r}{100}] + x[1 + \frac{2r}{100}] + x[1 + \frac{r}{100}]](https://tex.z-dn.net/?f=x%5B1%20%2B%20%5Cfrac%7B4r%7D%7B100%7D%5D%20%2B%20x%5B1%20%2B%20%5Cfrac%7B3r%7D%7B100%7D%5D%20%2B%20x%5B1%20%2B%20%5Cfrac%7B2r%7D%7B100%7D%5D%20%2B%20x%5B1%20%2B%20%5Cfrac%7Br%7D%7B100%7D%5D)
= 
= 
So, in case of Sam the sum will be = 
= $53750
