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Helga [31]
3 years ago
8

A 7-pack of plastic rings costs $2.52. What is the unit price? per ring?​

Mathematics
1 answer:
VikaD [51]3 years ago
4 0

Answer:

7 rings = $2.52

then 1 ring will cost = 1/7×2.52

= 0.36

Therefore 1 ring will cost $0.36.

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Please factor this equation: 6a^2 − 12a + 6
mote1985 [20]

Answer: 6(a-1)^2

Step-by-step explanation:

6a^2-12a+6

6(a^2-2a+1)

6(a-1)^2

8 0
3 years ago
What is the total number of outcomes if you there are three sizes of milk shakes (S,M.L) and five flavors of ice cream (Vanilla,
Elis [28]

5 small milkshake outcomes

5 medium milkshake outcomes

and

5 large milkshake outcomes

since there are only 5 flavors you can only make 5 different milkshakes unless you want to mix the flavors to make

5+10= 15 so you could make 15 that mixing each ice cream with each other and then mixing all of them.

5 0
3 years ago
What number has 1 ten thousand, 4 more thousands than ten thousands, 3 more
ASHA 777 [7]

Answer:

15884

Step-by-step explanation:

just follow the order easy

Brainliest

5 0
3 years ago
What is a problem that requires adding one two the quotient
Nikolay [14]

division problem

In a division problem, the number being divided into pieces is the dividend. The number by which the dividend is divided is called the divisor. And the answer to the division problem is the quotient.

6 0
2 years ago
The rate of growth of profit​ (in millions) from an invention is approximated by Upper P prime (x )equals x e Superscript negati
Alecsey [184]

Answer:

The function is  P(x) =  \frac{1}{2} e^{-x^2} +0.016

Step-by-step explanation:

From the question we are told that

    The rate of growth  is  P'(x) =  xe^{x} - x^2

     The total profit is P(2)  =$25,000

      The time taken to make the profit is x =  2 \ years

         

From the question

     P'(x) =  xe^{-x^2}  is the rate of growth

  Now here x represent the time taken

Now the total profit is mathematically represented as

       P(x) =  \int\limits {P'(x)} \,  =   \int\limits {xe^{-x^2}} \,

So using substitution method

   We have that

                      u =  - x^2

                      du =  2xdx

  So  

        p(x) =  \int\limits {\frac{1}{2} e^{-u}} \, du

       p(x) =  {\frac{1}{2} [ e^{-u}} +c ]

       p(x) =  {\frac{1}{2}  e^{-x^2}} + \frac{1}{2} c      recall  u =  - x^2   and  let  \frac{1}{2} c =  Z

       

At  x =  2 years  

     P(x)  =$25,000

So

       Since the profit rate is in million

    P(x)  =$25,000 = \frac{25000}{1000000} =$0.025 millon dollars

So  

       0.025 =  {\frac{1}{2}  e^{-2^2}} + Z  

=>    Z = 0.025 - {\frac{1}{2}  e^{-2^2}}  

       Z = 0.016  

So the profit function becomes

         P(x) =  \frac{1}{2} e^{-x^2} +0.016

     

       

5 0
3 years ago
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