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Andrej [43]
4 years ago
5

PLEASE HELP!! Will give brainliest if you give explanation!

Mathematics
1 answer:
MArishka [77]4 years ago
3 0
The equation in slope-intercept is   y=0.625x+7.    


y = mx + b

where: 
m is the slope of the line 
b is the y-intercept of the line

The slope m of the line through any two points (x1, y1) and (x2, y2) is given by:

The y-intercept b of the line is the value of y at the point where the line crosses the y axis. Since for point (x1, y1) we have y1 = mx1 + b, the y-intercept b can be calculated by:

b = y1 - mx<span>1.    hope that helped</span>

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Given cot A = 5/6 and that angle A is in Quadrant I, find the exact value of csc A in
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Answer: well search It up 1/10

Step-by-step explanation:

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How do you solve equations that contain multiplication or division
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Left to right. Whatever comes first (multiplication or division) you do. This is all part of the PEMDAS/Order of operations.

Hopefully I solved your problem! :)
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Resolve into partial fractions<br><br>​
lisabon 2012 [21]

Answer:

See below

Step-by-step explanation:

1)

\frac{11 + x}{(2 - x)(x - 3)}  =  \frac{A}{2 - x}  +  \frac{B}{x - 3}  \\  \\  \therefore \:  \frac{11 + x}{(2 - x)(x - 3)}  =  \frac{A(x - 3) +B(2 - x) }{(2 - x)(x - 3)}   \\  \\ \therefore \:  11 + x = Ax - 3A + 2B - Bx \\  \\  \therefore \: 11 + x = - 3A  + 2B  + Ax -  Bx\\  \\  \therefore \: 11 + x = - 3A  + 2B  + (A - B)x \\  \\ equating \: the \: like \: terms \: on \: both \: sides \\ A - B = 1 \\  \therefore \: A  =  B  +  1.....(1) \\  \\  -  3A  + 2B = 11....(2) \\  from \: eq \: (1) \: and \: (2) \\  - 3(B  +  1) + + 2B = 11 \\  \\ - 3B   - 3  + 2B = 11 \\  \\  - B = 11 + 3 \\  \\ B =  - 14  \\ A  =   - 14 +  1 =  - 13 \\  \\  \frac{11 + x}{(2 - x)(x - 3)}  =  \frac{ - 13}{2 - x}  +  \frac{ - 14}{x - 3} \\  \\ \frac{11 + x}{(2 - x)(x - 3)}  = -   \frac{ 13}{2 - x}   -  \frac{ 14}{x - 3}

2)

\frac{12x + 11}{x^2 +x - 6}

=\frac{12x + 11}{x^2 +3x-2x - 6}

=\frac{12x + 11}{x(x +3) -2(x +3)}

\therefore \frac{12x + 11}{x^2 +x - 6}=\frac{12x + 11}{(x +3) (x - 2)}

\therefore \frac{12x + 11}{x^2 +x - 6}=\frac{A}{(x +3)}+\frac{B}{(x - 2)}

\therefore \frac{12x + 11}{x^2 +x - 6}=\frac{A(x-2)+B(x+3)}{(x-2)(x+3)}

\therefore 12x + 11 = A(x-2)+B(x+3)

\therefore 12x + 11 = Ax-2A+Bx+3B

\therefore 12x + 11 = Ax+Bx-2A+3B

\therefore 12x + 11 = (A+B) x-2A+3B

Equating like terms on both sides:

A + B = 12\implies A = 12-B... (1)

- 2A + 3B = 11... (2)

Solving equations (1) & (2), we find:

A = 5, B = 7

\therefore \frac{12x + 11}{x^2 +x - 6}=\frac{5}{(x +3)}+\frac{7}{(x - 2)}

3 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match the verbal descriptions with the co
Daniel [21]

Answer:

Step-by-step explanation:

6 more than a number is 36: x+6=36

36 more than a number is 6: x+36=6

6 times a number is 36: 6x=36

4 0
3 years ago
6. Which process was used to obtain the equation shown in Step 2?
frozen [14]

Answer:

A) added to both sides of the equation

Step-by-step explanation:

3 0
3 years ago
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