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luda_lava [24]
3 years ago
13

if the xy-plane, the graph of y=x^2 and the circle with center (0,1) and radious 3 have how many points of intersection?

Mathematics
1 answer:
Rashid [163]3 years ago
6 0
\bf \textit{equation of a circle}\\\\
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{cases}
center\ ({{ h}},{{ k}})\\
radius={{ r}}\\
----------\\
center\ (0,1)\to 
\begin{cases}
h=0\\
k=1
\end{cases}\\
r=3
\end{cases} 
\\\\\\
(x-0)^2+(y-1)^2=3^2\implies x^2+(y-1)^2=9
\\\\\\
(y-1)^2=9-x^2\implies y=\sqrt{9-x^2}+1\\\\
-----------------------------\\\\
\textit{where do the parabola and circle intersect? set them to equal}
\\\\\\



\bf \begin{cases}
y=x^2\\\\
y=\sqrt{9-x^2}+1
\end{cases}\qquad y=y\implies  x^2=\sqrt{9-x^2}+1

solve for "x"
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Step-by-step explanation:

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b). Since ΔOPQ ~ ΔRTS, their corresponding sides will be proportional.

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