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aleksklad [387]
4 years ago
13

Solve for x: 4+7x-3x+2=8x+6

Mathematics
1 answer:
blondinia [14]4 years ago
3 0

4 + 7x - 3x + 2 = 8x + 6
6 + 4x = 8x + 6
Subtract 6 and 4x from both sides
0 = 4x
0 = x
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Please answer these last four questions.
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Answer:

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Step-by-step explanation:

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Evaluate x + 4 when x = 3
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If x2=18x+y and y2=18y+x, then find the value of root
mezya [45]

Answer:

\sqrt{x^2+y^2+1}=18

Step-by-step explanation:

We are given:

x^2=18x+y\qquad\qquad[1]

y^2=18y+x\qquad\qquad[2]

Subtracting [1] and [2]:

x^2-y^2=18x+y-(18y+x)

Operating:

x^2-y^2=18x+y-18y-x

Recall:

x^2-y^2=(x-y)(x+y)

Substituting:

(x-y)(x+y)=18x+y-18y-x

Rearranging:

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(x-y)(x+y)=18(x-y)-(x-y)

Dividing by x-y (recall x≠y):

x+y=18-1=17

x+y=17\qquad[3]

Now we add [1] and [2]:

x^2+y^2=18x+y+18y+x

Rearranging:

x^2+y^2=18x+18y+x+y

x^2+y^2=18(x+y)+(x+y)

x^2+y^2=19(x+y)

Substituting from [3]

x^2+y^2=19*17=323

Adding 1:

x^2+y^2+1=324

Taking the square root:

\sqrt{x^2+y^2+1}=\sqrt{324}=18

Thus:

\mathbf{\sqrt{x^2+y^2+1}=18}

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