Answer:
x^3-4x^2+25x-100
Step-by-step explanation:
We have 2 roots -5i and 4. Using the conjugate root theorem for the root -5i, we know that 5i should be another root
Combining the roots into a polynomial gives us:
(x+5i)(x-5i)(x-4)
Expand:
(x^2 + 25)(x-4)
x^3-4x^2+25x-100
Answer:
Original number = 38
Step-by-step explanation:
10*x + y
x = y - 5
10y + x = 2 (10x + y) + 7
10y + y - 5 = 2(10(y - 5) + y) + 7
11y - 5 = 2(10y - 50 + y ) + 7
11y - 5 = 2(11y - 50) + 7
11y - 5 = 22y - 100 + 7
11y - 5 = 22y - 93
11y + 88 = 22y
88 = 11y
y = 8
x = y - 5
x = 8 - 5
x = 3
So the original number is 38. Does that work?
3 is 5 less than 8.
83 = 2*38 + 7
83 = 76 + 7
83 = 83. Yes it works.
D.y = 10x + 250
y = 12x + 150 is the correct answer to the question
Answer:
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Answer: negative 8 or -8
Step-by-step explanation:
would include explanation but it would take a while hope it helped and may i have brainliest please?!