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hram777 [196]
3 years ago
8

Find the equation of a line that is perpendicular to a line whose equation is 6x - y = -1 and passes through the point ( -1, 5 )

. This is very difficult for me help would be greatly appreciated!
Mathematics
1 answer:
Svet_ta [14]3 years ago
4 0
-y=-6x-1
-1(-y=-6x-1)
y=6x+1
5=6(-1)+b
5=-6+b
b=11

y-1/6x+11
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nalin [4]

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The solutions of given equation in the range [0, 2\pi) i.e. 0 can be in the answer but 2\pi can not be there in the answer.

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Taking tan(x) common, we get:

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0, \dfrac{\pi}{6}, \dfrac{5\pi}{6},  \pi

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