Help with 1-3 show work on how got the answer to be marked as brainliest

Mathematics

1 answer:

MatroZZZ [7]3 years ago

7 0

B.) 10 The length of the board is 7×12 = 84
the largest number of 15 inch pieces that
jeremy can cut is 5. 84÷15 is a quotient of
5 with a remainder of 9. 5×5=10

You might be interested in

a nunber is multiplied by 2. then that product is multiplied by 5. write to explain how you know what digit is in the ones place

siniylev [52]

Any number multiplied by 2 will give u an even number.
2 x 3 = 6
2 x 4 = 8
2 x 5 = 10

and any even number multiplied by 5 will end in 0
5 x 2 = 10
5 x 4 = 20
5 x 6 = 30

so the number in the ones place will be 0

6 0

3 years ago

PLEASE HELP ME URGENT PLEASE

cupoosta [38]

Answer:

Step-by-step explanation:

5 0

1 year ago

A and b together can do a piece of work in 8 days. If a alone can do the same work in 12 days, then b alone can do the same work

Nostrana [21]

B can finish the job alone in 24 days.

In work-rate problems, a certain person can complete a fraction of the job for a specific timeframe. As stated in the problem, A and B can finish the job by working together for 8 days. It must be noted that the fraction of the job they can finish individually per day is additive.

$\frac{1}{A} + \frac{1}{B} = \frac{1}{8}$

A can complete the work in 12 days and finish 1/12 fraction of a job per day. This can be substituted directly to the equation to solve for the time B needed to finish the work.

$\frac{1}{12} + \frac{1}{B} = \frac{1}{8}$

$\frac{1}{B}= \frac{1}{8}- \frac{1}{12}$

$\frac{1}{B} = \frac{1}{24}$

This means that B can do 1/24 fraction of the job per day and can completely finish the job in 24 days.

For more rate work-rate problems, please refer to the link brainly.com/question/14464103.

#SPJ4

6 0

2 years ago

Find an nth-degree polynomial function with real coefficients satisfying the given conditions.

lesya692 [45]

Answer:

$\displaystyle f(x) = -2(x-2)(x^2+4)$

Step-by-step explanation:

We want to find a third degree polynomial with zeros x = 2 and x = 2i and f(-1) = 30.

First, note that by the Complex Root Theorem, since x = 2i is a root, x = -2i must also be a root.

Hence, we will have the three factors:

$\displaystyle f(x) = a(x-(2))(x-(2i))(x-(-2i))$

Where a is the leading coefficient.

Expand and simplify the second and third factors:

$\displaystyle \begin{aligned} (x-(2i))(x-(-2i)) &= (x-2i)(x+2i) \\ \\ &= x(x-2i)+2i(x-2i) \\ \\ &= (x^2 - 2ix) + (2ix - 4i^2) \\ \\ &=x^2 + 4\end{aligned}$