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adelina 88 [10]
3 years ago
10

you have one case of soap bars and there are 150 bars in a case you use 300 bars of soap per day how many cases do you need to o

rder to have for enough for 7 days
Mathematics
2 answers:
Serhud [2]3 years ago
6 0
21 barras de sabão por dia que precisa
Charra [1.4K]3 years ago
4 0
The Answer to your question is 14 cases for 7 days
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The answer to this problem is 144 square units.
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Is the percent increase from 50 to 70 equal to the percent decrease from 70 to 50? Explain.
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Answer:

  • No

Step-by-step explanation:

  • <em>Percent change is the difference in numbers divided by initial number converted to percent value.</em>

<u>Percent increase:</u>

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<u>Percent decrease:</u>

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<u>Compare:</u>

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What is 3.4 in fraction
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\rm 3,4= \frac{34}{10}\\\\We\ can\ simplify\ this\ fraction:\\\\\  \frac{34\div2}{10\div2}=\boxed{ \frac{17}{5} }

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3 years ago
1) What is the solution of the given system?
m_a_m_a [10]

Answer:

1  x=-2.5  y = -5.5

2.  x=5  y=1

Step-by-step explanation:

1) What is the solution of the given system?

5x-y=-7

3x-y=-2

Multiply the second equation by -1

-1*(3x-y)=-1(-2)

-3x +y = 2


Now add the first equation to the modified second equation

5x-y=-7

-3x +y = 2

------------------

2x = -5

Divide each side by 2

2x/2 = -5/2

x = -2.5

Now we need to find y

-3x+y =2

-3(-2.5) +y =2

7.5 +y =2

Subtract 7.5 from each side

7.5 -7.5 +y =2-7.5

y = -5.5


2) what is the solution of the given system?

5x+7y=32

8x+6y=46

Divide the second equation by 2

8x/2+6y/2=46/2

4x+3y =23


Multiply the first equation by 4

4 (5x+7y)=32*4

20x+28y = 128


Now multiply the modified 2nd equation by -5

-5(4x+3y )=-5(23 )

-20x -15y = -115


Lets add the new equations together to eliminate x

20x+28y = 128

-20x -15y = -115

---------------------

      13y = 13

Divide each side by 13

13y/13 =13/13

y=1

Now substitute back in to find x

5x+7y=32

5x +7(1) =32

5x +7 =32

Subtract 7 from each side

5x+7-7 =32-7

5x =25

Divide by 5

5x/5 =25/5

x=5





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Answer:

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Step-by-step explanation:

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