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3 years ago

15

What is the range of the absolute value function below?

2 answers:

Kobotan [32]3 years ago

7 0

The answer is c f(x) < 1

ivann1987 [24]3 years ago

3 0

Answer:

f(x) ≤1

Step-by-step explanation:

The range involves the y-axis, whereas the domain involves the x-axis. The range is the area between the highest point and lowest point. So for this question, the highest point is 1 and there is no lowest point because the line doesn't end. If there's an open circle on the point the sign changes to <, but a closed circle is ≤. That's how we get f(x) ≤ 1.

I know it's confusing, but I hope this helped a little bit.

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Virty [35]

<u>Answer-</u>

$\boxed{\boxed{\dfrac{\widehat{BC}}{\widehat{DE}}=\dfrac{3}{4}}}$

<u>Solution-</u>

We know that arc length is the product of radius and central angle in radian.

i.e $\text{Arc length}=\text{Radius}\times \text{Central angle}$

Here,

$\theta_{BC}=1.18\ rad,\ \theta_{DE}=2.36\ rad\\\\AD=\dfrac{2}{3}AB\Rightarrow AB=\dfrac{3}{2}AD$

So,

$\dfrac{\widehat{BC}}{\widehat{DE}}=\dfrac{AB\times 1.18}{AD\times 2.36}$

$=\dfrac{\frac{3}{2}AD\times 1.18}{AD\times 2.36}$

$=\dfrac{3\times 1}{2\times 2}$

$=\dfrac{3}{4}$

4 0

3 years ago

Factor this equation 75k^2+30k=-3

Solnce55 [7]

Answer:

k=-1/5

Step-by-step explanation:

Factor and set each factor equal to zero.

Add 3 to both sides of the equation.

75k^2+30k+3=0

Factor 3 out of 75k^2+30k+3.

Factor using the perfect square rule.

Divide each term by 3 and simplify.

Set the 5k+1 equal to 0.

Solve for k.

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Ghella [55]

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Ludmilka [50]

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SashulF [63]

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Step-by-step explanation:

:/

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