I need help on this question

Mathematics

2 answers:

BaLLatris [955]4 years ago

5 0

Well this decagon has 10 equal sides so all we have to do is divide 360 by 10 to find the measure of the interior angles. 360/10 = 36 So the interior angles are 36º

I hope this helps

-Ayden

MatroZZZ [7]4 years ago

3 0

The interior angles are 36 degrees.

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You are baking brownies for your class. There are 28 total students in your class and you have baked 23 brownies. Write and solv

barxatty [35]

Answer:

2(28)=23+x

Step-by-step explanation:

There are 28 students and each student needs two brownies. You have to multiply 28 by 2 so you will have to total number on one side.

On the other you need to have the number of brownies you have at the moment and x for the number you need to bake. You want to add them because you will need to put those numbers together to get the number on the opposite side.

28x2=56 so 56=23+x. Subtract the 23 from both sides to get 33=x. x=33

To check plug 33 into x to get 2(28)=23+33. 56=23+33. 56=56

you need 33 more brownies.

So the equation would be 2(28)=23+x.

Hope that helps.

3 0

3 years ago

In screenshot ı didn t understand this question

aniked [119]

Answer:

cool neither do i

Step-by-step explanation:

3 0

3 years ago

Solve <img src="https://tex.z-dn.net/?f=-2x%5E2%20%2B3x%20-%209%20%3D%200" id="TexFormula1" title="-2x^2 +3x - 9 = 0" alt="-2x^2

MArishka [77]

Answer:

$x= \frac{3-3\sqrt{7}i }{4}$ and $x= \frac{3+3\sqrt{7}i }{4}$

Step-by-step explanation:

We have to solve the given equation - 2x² + 3x - 9 = 0

To solve the equation given above we have to factorize the left-hand side of the equation.

But it can not be factorized. So, use the Sridhar Achaya formula.

Therefore, $x= \frac{-3 + \sqrt{3^{2}-4 \times (-2) \times (-9) } }{2\times (-2)}$ and $x= \frac{-3 -\sqrt{3^{2}-4 \times (-2) \times (-9) } }{2\times (-2)}$

So, $x= \frac{3-3\sqrt{7}i }{4}$ and $x= \frac{3+3\sqrt{7}i }{4}$ {Where $i=\sqrt{-1}$ }

Therefore, the solutions are imaginary numbers. (Answer)

Note: The Sridhar Acharya Formula gives if ax² + bx + c = 0, then the roots of the equation are $x = \frac{-b + \sqrt{b^{2}-4ac } }{2a}$ and $x = \frac{-b - \sqrt{b^{2}-4ac } }{2a}$ .