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4 years ago

Both of these please and thank you!!!!!

Mathematics

1 answer:

Tom [10]4 years ago

7 0

Answer:

1. 3x^2 + 4x - 5 = 0

x₁ = (-2 + √19)/3

x₂ = (-2 - √19)/3

2. X^2 - 13x + 42 = 0

x₁ = 7

x₂ = 6

Step-by-step explanation:

1. Let's solve for x using the quadratic formula this way:

3x^2 + 4x - 5 = 0

x = [-4 +/- √(4² - 4 * 3 * -5)]/2 * 3

x = [-4 +/- √(16 + 60)]/6

x = [-4 +/- √76]/6

x = [-4 +/- 2√19]/6 (√76 =√4 * 19)

x = -2 +/- √19/3

x₁ = (-2 + √19)/3

x₂ = (-2 - √19)/3

2. Let's solve for x, factoring this way:

X^2 - 13x + 42 = 0

(x - 7) (x - 6) = 0

x₁ = 7

x₂ = 6

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