Answer:
When Microsoft switched to XML-based file formats in Office 2007, they added the 'x' to the file extensions to differentiate from the previous, incompatible formats such as dox to docx.
In other words. X is extended.
Answer:
Select the text and then press Shift + F3 until the case you want is applied.
Answer:
int i = 0; i < names.size(); i++
Explanation:
The ArrayList must be read in the forward direction, and it is going to start from 0 certainly. Also, the iteration is going to end when i is exactly one less than the size of the ArrayList. And this is possible only if we choose the option mentioned in the Answer section. In this, i starts from 0 and iterates till i is one less than name.size() which is the size of the ArrayList.
Answer:
See in Explanation
Explanation:
All you know is that an 
algorithm is eventually (a lot) faster than an 
algorithm, but for any specific value of n, you can't say anything. Indeed, the asymptotic growth of the function doesn't depend on its value on 
. This means that if 
then for all 
, the following function is also :
So asymptotic notation is completely uninformative regarding the performance of algorithms on specific values of n.
You could say that functions such as 
are artificial and never really occur in practice. This is not quite true (you can hard-code some auxiliary information for small n, for example), but even if you consider "natural" functions, asymptotic notation doesn't help you to determine anything other than asymptotic's: consider for example 
against 
(such examples definitely happen in practice, for example in fast matrix multiplication).
The following code will program that prompts the user to enter the num- ber of hours a car is parked at the airport and outputs the parking fee.
<u>Explanation:</u>
Code:
#include<iostream>
using namespace std;
int main()
{
float hours;
cout <<"Enter number of hours a car parked at the airport: "; // prompt the user to enter hours.
cin >> hours ; // strong the hours
if (hours > = 0 && hours < =3 ) // if 0 < = h < = 3
cout << "Parking fee: 5"; //printing parking fee is 5.
else if (hours > 3 && hours < = 9)//if 3 < h < = 9
cout<<"Parking fee: "<<6*int(hours);//converting float value to int the multiplying with 6 then printing fee.
else//if 9 < h < = 24
cout<< "Parking fee: 60";// printing parking fee 60.
return 0;
}
