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Llana [10]
4 years ago
15

The formula for the surface area of a pyramid is: SA=1/2LP+B . which equation solves formula for p

Mathematics
1 answer:
jeka944 years ago
6 0
S_A=\frac{1}{2}LP+B\\\\\frac{1}{2}LP+B=S_A\ \ \ \ \ \ |subrtact\ "B"\ from\ both\ sides\\\\\frac{1}{2}LP=S_A-B\ \ \ \ \ |multiply\ both\ sides\ by\ 2\\\\LP=2S_A-2B\ \ \ \ \ \ |divide\ both\ sides\ by\ "L"\\\\P=\frac{2S_A-2B}{L}
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How to subtract fractions
frosja888 [35]
You need to first make denominator in the fractions you have equal, then simply subtract numenators.

example:
2/3 - 1/2
first step is to make denominators equal.
for this example, the denominator will be equal to 6 which is 2x3
so, 2/3 = 4/6 and 1/2 = 3/6
so, the expression now becomes:
4/6 - 3/6
simply subtract numenators and the denominator will be 6 as well.
4/6 - 3/6 = 1/6

another example:
3/4 - 1/2
here the denominator can be equal to 4 in all terms
1/2 = 2/4
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5 0
4 years ago
Find the greatest common factor of the following monomial.<br> 37x^3y^6 x^6y^2
nordsb [41]
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</span>greatest common factor: x^3y^2
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What is the solution to the proportion? 5/x = 2/8 ( It's in fraction form lol)
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7 0
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Read 2 more answers
An article in Fire Technology investigated two different foam-expanding agents that can be used in the nozzles of firefighting s
UNO [17]

Answer:

Step-by-step explanation:

Hello!

The objective of this experiment is to test if two different foam-expanding agents have the same foam expansion capacity

Sample 1 (aqueous film forming foam)

n₁= 5

X[bar]₁= 4.7

S₁= 0.6

Sample 2 (alcohol-type concentrates )

n₂= 5

X[bar]₂= 6.8

S₂= 0.8

Both variables have a normal distribution and σ₁²= σ₂²= σ²= ?

The statistic to use to make the estimation and the hypothesis test is the t-statistic for independent samples.:

t= \frac{(X[bar]_1 - X[bar]_2) - (mu_1 - mu_2)}{Sa*\sqrt{\frac{1}{n_1} + \frac{1}{n_2 } } }

a) 95% CI

(X[bar]_1 - X[bar]_2) ± t_{n_1 + n_2 - 2}*Sa* \sqrt{\frac{1}{n_1}+\frac{1}{n_2} }

Sa²= \frac{(n_1-1)S_1^2 + (n_2-1)S_2^2}{n_1 + n_2 - 2}= \frac{(5-1)0.36 + (5-1)0.64}{5 + 5 - 2}= 0.5

Sa= 0.707ç

t_{n_1 + n_2 -2: 1 - \alpha /2} = t_{8; 0.975} = 2.306

(4.7-6.9) ± 2.306* (0.707\sqrt{\frac{1}{5}+\frac{1}{5} })

[-4.78; 0.38]

With a 95% confidence level you expect that the interval [-4.78; 0.38] will contain the population mean of the expansion capacity of both agents.

b.

The hypothesis is:

H₀: μ₁ - μ₂= 0

H₁: μ₁ - μ₂≠ 0

α: 0.05

The interval contains the cero, so the decision is to reject the null hypothesis.

<u>Complete question</u>

a. Find a 95% confidence interval on the difference in mean foam expansion of these two agents.

b. Based on the confidence interval, is there evidence to support the claim that there is no difference in mean foam expansion of these two agents?

8 0
3 years ago
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Masteriza [31]

Answer: 5 8 7 9 5 6

Step-by-step explanation:

Because you go by which is closer to the denominator

8 0
3 years ago
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