3 years ago

The formula for the surface area of a pyramid is: SA=1/2LP+B . which equation solves formula for p

1 answer:

jeka943 years ago

6 0

$S_A=\frac{1}{2}LP+B\\\\\frac{1}{2}LP+B=S_A\ \ \ \ \ \ |subrtact\ "B"\ from\ both\ sides\\\\\frac{1}{2}LP=S_A-B\ \ \ \ \ |multiply\ both\ sides\ by\ 2\\\\LP=2S_A-2B\ \ \ \ \ \ |divide\ both\ sides\ by\ "L"\\\\P=\frac{2S_A-2B}{L}$

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Solve the equation. Check for extraneous solutions. Type your answers in the blanks. Show your work. |4x+3| = 9+2x

GaryK [48]

Answer:

Step-by-step explanation:

|4x + 3| = 9 + 2x

We see the absolute value so we have to consider 2 cases:

(1)

4x + 3 = -9 - 2x

6x = -12

x = -2

(2)

4x + 3 = 9 + 2x

2x = 6

x = 3

Let's plug in both results.

|4(-2) + 3| = 9 + 2(-2)

|-5| = 9 - 4

5 = 5

Therefore x = -2 is a solution

|4(3) + 3| = 9 + 2(3)

|15| = 9 + 6

15 = 15

Therefore x = 3 is also a solution.

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3 years ago

Factor the quadratic equation below to reveal the solutions. X^2+4x-21=-9

a_sh-v [17]

Answer:

x = 3 and x = -7

Step-by-step explanation:

The given quadratic equation is $x^2+4x-21=0$ . We need to find the solution of this equation.

If the equation is in the form of $ax^2+bx+c=0$ , then its solutions are given by :

$x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}$

Here, a = 1, b = 4 and c = -21

Plugging all the values in the value of x, such that :

$x=\dfrac{-b+ \sqrt{b^2-4ac} }{2a},\dfrac{-b- \sqrt{b^2-4ac} }{2a}\\\\x=\dfrac{-4+ \sqrt{(4)^2-4\times 1\times (-21)} }{2(1)},\dfrac{-4- \sqrt{(4)^2-4\times 1\times (-21)} }{2(1)}\\\\x=3, -7$