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Llana [10]
3 years ago
15

The formula for the surface area of a pyramid is: SA=1/2LP+B . which equation solves formula for p

Mathematics
1 answer:
jeka943 years ago
6 0
S_A=\frac{1}{2}LP+B\\\\\frac{1}{2}LP+B=S_A\ \ \ \ \ \ |subrtact\ "B"\ from\ both\ sides\\\\\frac{1}{2}LP=S_A-B\ \ \ \ \ |multiply\ both\ sides\ by\ 2\\\\LP=2S_A-2B\ \ \ \ \ \ |divide\ both\ sides\ by\ "L"\\\\P=\frac{2S_A-2B}{L}
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Mr. Parker wants to rent a cargo van for a day. It will cost the daily fee of $50 plus $0.35 per mile driven. Let m = the number
Iteru [2.4K]

Answer:

<h2>y=0.35m+50</h2>

Step-by-step explanation:

Step one:

given data

the daily fee= $50

cost per mile driven =$0.35

Let m = the number of miles

let y be the total cost

Step two

Required

the expression for the total cost is

An algebraic expression that shows the amount he will pay for the van. is  

<em>y=0.35m+50</em>

4 0
3 years ago
Evaluate the following integrals: 1. Z x 4 ln x dx 2. Z arcsin y dy 3. Z e −θ cos(3θ) dθ 4. Z 1 0 x 3 √ 4 + x 2 dx 5. Z π/8 0 co
Zigmanuir [339]

Answer:

The integrals was calculated.

Step-by-step explanation:

We calculate integrals, and we get:

1) ∫ x^4 ln(x) dx=\frac{x^5 · ln(x)}{5} - \frac{x^5}{25}

2) ∫ arcsin(y) dy= y arcsin(y)+\sqrt{1-y²}

3) ∫ e^{-θ} cos(3θ) dθ = \frac{e^{-θ} ( 3sin(3θ)-cos(3θ) )}{10}

4) \int\limits^1_0 {x^3 · \sqrt{4+x^2} } \, dx = \frac{x²(x²+4)^{3/2}}{5} - \frac{8(x²+4)^{3/2}}{15} = \frac{64}{15} - \frac{5^{3/2}}{3}

5)  \int\limits^{π/8}_0 {cos^4 (2x) } \, dx =\frac{sin(8x} + 8sin(4x)+24x}{6}=

=\frac{3π+8}{64}

6)  ∫ sin^3 (x) dx = \frac{cos^3 (x)}{3} - cos x

7) ∫ sec^4 (x) tan^3 (x) dx = \frac{tan^6(x)}{6} + \frac{tan^4(x)}{4}

8)  ∫ tan^5 (x) sec(x)  dx = \frac{sec^5 (x)}{5} -\frac{2sec^3 (x)}{3}+ sec x

6 0
3 years ago
Help!!!!!! I’ll give 100 points
Mama L [17]

Answer:

your answer is c :)

7 0
3 years ago
Read 2 more answers
Mhanifa please help me with this? I will mark brainliest!
alekssr [168]

Answer:

C. 20

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Help me out hunnys ❤️
Alenkinab [10]

Answer:

g(x)=3(x+3)^2-8

Step-by-step explanation:

You can solve by using these acronyms.


H. orozontal.

I. nside.

O. pposite.


Meaning that a horozontal translation would be written inside the parenthesis and the poopsite sigh you would usually (Ex. Left is usually negitave but in this case it is positive).


The other acronym is,


V. erticle.

O. utside.

S. ame.


Meaning for a vrerticle translation the number would go on the outside of the parenthesis and tha sign would be normal (Ex. Negitave would be left and positive would be right).


For this one use H.I.O sinse you are moving on a horozontal plain. You are only working with the (x-2) nothing else matters.


Since you are moving left the number will move up 3 hence the O.


<h2><u>This transformation leaves you with g(x)=3(x+3)^2-8</u></h2>



3 0
3 years ago
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