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wlad13 [49]
4 years ago
15

Suppose you own a travel agency in a large city. You have many corporate clients, but growth has slowed somewhat Some long-term

employees are getting discouraged, but you feel that there might be a way to make technology work in your favor. Use your imagination and suggest at least one strength, weakness, opportunity, and threat that your business faces.
Computers and Technology
1 answer:
kherson [118]4 years ago
8 0

Explanation:

For any business or organisation, a strategic planning is a road map leading to a successful future. SWOT planning and analysis makes contribution to that strategic planning processes by identifying the various labor, technical and financial resources. SWOT stands for --

S - Strength

W - Weakness

O - Opportunity

T - Threat

One such strength of our business is we have a great and commendable employee retention.

Weakness is that we have not utilize technology properly to attract the customers. Also we need to update to our software.

An opportunity is that we can explore many technological solutions for the problems that causes growth issues. Also we can be the first in the niche market to use such technologies thus attracting customers.

And a threat is that we adapting to changing internet and as well as technology climate can lead to our business failing.

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Which type of security personnel may work for government as well as for private security agencies?
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Answer: A security guard

Explanation:

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3 years ago
Read 2 more answers
Write a main program that prompts users for 5 integers. Use two separate functions to return (NOT print) the highest and lowest
Soloha48 [4]

Answer:

import java.util.Arrays;

import java.util.Scanner;

public class LatinHire {

   public static void main(String[] args) {

       Scanner in = new Scanner (System.in);

       System.out.println("Enter Five integers");

       int num1 = in.nextInt();

       int num2 = in.nextInt();

       int num3 = in.nextInt();

       int num4 = in.nextInt();

       int num5 = in.nextInt();

       int [] intArray = {num1,num2,num3,num4,num5};

       System.out.println(Arrays.toString(intArray));

       System.out.println("The Maximum is "+returnMax(intArray));

       System.out.println("The Minimum is "+returnMin(intArray));

   }

   public static int returnMax(int []array){

       int max = array[0];

       for(int i=0; i<array.length; i++){

           if(max<array[i]){

               max= array[i];

           }

       }

       return max;

   }

   public static int returnMin(int []array){

       int min = array[0];

       for(int i=0; i<array.length; i++){

           if(min>array[i]){

               min= array[i];

           }

       }

       return min;

   }

}

Explanation:

  1. This is implemented in Java Programming Language
  2. Two Methods are created returnMax(Returns the Maximum Value of the five numbers) and returnMin(Returns the minimum of the five numbers)
  3. In the Main method, the user is prompted to enter five numbers
  4. The five numbers are saved into an array of integers
  5. The returnMax and returnMin methods are called and passed the array as parameter.
  6. The entire array of numbers inputted by the user as well the Max and Min are printed

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Under normal operations, cisco recommends that you configure switch ports on which vlan
larisa86 [58]

 

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3 years ago
In spreadsheets, a cell reference is also referred to as which of the following? A. active cell B. axis C. cell address D. entry
nignag [31]
Generally its referring to the cells location, so C.
4 0
3 years ago
Create an application containing an array that stores eight integers. The application should call five methods that in turn (1)
Butoxors [25]

Answer:

package b4;

public class ArrayMethodDemo {

public static void main(String[] args) {

 // Create an array to store 8 random integers.

 int[] integernumbers = { 3, 4, 6, 9, 5, 6, 7, 2 };

 // Call the display method to show the elements in the array.

 display(integernumbers);

 // Call the method to display the elements in reverse order.

 displayReverse(integernumbers);

 // Call the method to find the sum of the elements.

 sum(integernumbers);

 // Call the method to display all elements less than a limiting value, say 5.

 lessThan(integernumbers, 5);

 // Call the method to display all elements greater than the average of the array

 // elements.

 higherThan(integernumbers);

}

// Method to display the elements in the array.

// The method receives only a single argument which is the array.

// Loop through the array and at every cycle, print out each element

public static void display(int[] arr) {

 System.out.print("All integers in the array : ");

 for (int i = 0; i < arr.length; i++) {

  System.out.print(arr[i] + " ");

 }

 System.out.println();

}

// Method to display the elements in the array in reverse order

// The method receives only a single parameter which is the array

// Loop through the array starting at the last index

// At every cycle, print out the elements in the array

public static void displayReverse(int[] arr) {

 System.out.print("All integers in the array in reverse : ");

 for (int i = arr.length - 1; i >= 0; i--) {

  System.out.print(arr[i] + " ");

 }

 System.out.println();

}

// Method to print out the sum of the elements in the array.

// The method receives only a single parameter which is the array.

// Declare a variable called sum to hold the sum of the elements

// Initialize sum to zero

// Loop through the array and cumulatively add each element to sum

// Print out the sum at the end of the loop

public static void sum(int[] arr) {

 int sum = 0;

 for (int i = 0; i < arr.length; i++) {

  sum += arr[i];

 }

 System.out.println("The sum of the integers in the array is " + sum);

}

// Method to print all values in the array that are less than a limiting

// argument.

// The method has two parameters - the array and the limiting argument.

// Loop through the array and at every cycle,

// check if the current array element is less than the limiting argument.

// If it is, print it out. Else continue

public static void lessThan(int[] arr, int limitingargument) {

 System.out.print("All values less than the limiting argument (" + limitingargument + ") are: ");

 for (int i = 0; i < arr.length; i++) {

  if (arr[i] < limitingargument) {

   System.out.print(arr[i] + " ");

  }

 }

 System.out.println();

}

// Method to print all values in the array that are higher than the average of

// the array.

// The method has one parameter - the array.

// First, calculate the average of the array elements.

// Loop through the array and at every cycle,

// check if the current array element is greater than the average.

// If it is, print it out. Else continue

public static void higherThan(int[] arr) {

 int sum = 0;

 for (int i = 0; i < arr.length; i++) {

  sum += arr[i];

 }

 double average = sum / arr.length;

 System.out.print("All values higher than the calculate average (" + average + ") is ");

 for (int i = 0; i < arr.length; i++) {

  if (arr[i] > average) {

   System.out.print(arr[i] + " ");

  }

 }

 System.out.println();

}

}

Explanation:

The program has been written in Java.

Please go through the comments in the code for explanation.

The source code has also been attached to this response.

Hope this helps!

Download java
3 0
3 years ago
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