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Luba_88 [7]
3 years ago
7

What is the lenth of SR

Mathematics
1 answer:
iogann1982 [59]3 years ago
5 0
The length is SR is 15 units
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Heeelp me please ..?
Reptile [31]
Alright so first you want to find out how you take 30% off of $30.  The first step is to ask yourself, what's 30% of $30? All you have to do is make the percentage into a decimal like you did and multiply .30 times 30.  That gets you 9.  So 9 is 30% of $30, but since it said the original 30 was marked down by that much, it means subtract. 30-9=21.  
For the second part, you pretty much do the same thing but using the 21 you just got and taking away 20% this time.  Same process so .20 times 21=4.2, and take the 4.2 away from 21 to get 21-4.2=16.8.
Convert that to dollars to see that the final price is $16.80.  
Just a tip, a lot of people will forget the subtraction part after they find the percentage part.  Most of these type questions are two steps like that so don't forget to subtract when needed. Lmk if you still have questions :)
7 0
3 years ago
Graph each function over a one-period interval. y= -2 sec1/2x
kaheart [24]
<span>y =  3 cos(x) + 1. Your welcome :)

</span>
6 0
3 years ago
How to solve and get x and y
TiliK225 [7]
X=-3 and y=1 Hope this helps!

5 0
3 years ago
Use the function f(x) = 2x3 - 3x2 + 7 to complete the exercises. f(−1) =
omeli [17]
F ( -1 ) = 2 · ( -1 )³ - 3 · ( -1 )² +7 =
= 2 · ( -1 ) - 3 · 1 + 7=
= - 2 - 3 + 7 = 2

7 0
3 years ago
Harry drove 2 hours on the freeway then decreased his speed by 20mph and drove 6 more hours. total trip was 352 what was his spe
poizon [28]
Recall your d = rt, distance = rate * time

we know the total trip was 352miles, so, let's say he was going for the first 2hrs at "r" speed, he went "d" miles, then he slowed down to "r - 20" and went 6 more hours, since the total trip is 352 miles, the 6hrs take the slack from 352 - d, and that's how many miles he covered on those 6hours

\bf \begin{array}{lccclll}&#10;&distance&rate&time\\&#10;&-----&-----&-----\\&#10;\textit{before slowing}&d&r&2\\&#10;\textit{after slowing}&352-d&r-20&6&#10;\end{array}&#10;\\\\\\&#10;&#10;\begin{cases}&#10;\boxed{d}=2r\\&#10;352-d=(r-20)6\\&#10;----------\\&#10;352-\boxed{2r}=(r-20)6&#10;\end{cases}

solve for "r".
7 0
4 years ago
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