Probability of distinct 3-digits is 1/6.
Probability of both the first digit and the last digit are even numbers is 1/5.
<u>Step-by-step explanation</u>:
Given set of numbers {1,2,3,5,8,9} = 6
Total number of 3-digits can be formed = 654 = 120.
<u>Probability of the three-digit numbers with distinct digits</u> :
The number of 3-digit numbers with distinct digits = (654) / (321) = 20.
P(distinct 3-digits) = no. of distinct 3-digits / Total no.of 3-digits
⇒ 20/120
⇒ 1/6
<u>Probability that both the first digit and the last digit of the three-digit number are even numbers</u> :
The even numbers in the set are 2 and 8 = 2 possibilities.
The number of 3-digits with 1st and 3rd digit are even = (262) = 24.
P(1st and 3rd digits even)= no. of 1st and 3rd digit even/Total no. of 3-digits.
⇒ 24/120
⇒ 1/5
Do radius to the second power times pi
Answer: (-1,0)
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Explanation:
A quick method is to simply look at the graph and notice the two altitudes cross at (-1,0)
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A longer method involves a bit of algebra but its not too bad
y = x+1
y = -1+1 ... plug in x = -1 (ie replace x with -1)
y = 0
So when x = -1, the value of y is y = 0
They pair up to get (x,y) = (-1,0) which confirms what the graph is showing
The answer is B
Because when you graph it in the calculator you get x=-136 and that goes to one to one function on the graph