Seventy-five times an integer, minus 36, equals 21 times the square of the integer. Which equation could be used to solve for th
e unknown integer?
2 answers:
Answer:
The answer would be 21x2 − 75x + 36 = 0
Step-by-step explanation:
<u><em>21x2 − 75x + 36</em></u>
75x − 36 = 21x2
21x2 + 75x − 36 = 0
3(x + 4)(7x − 3) = 0
x = −4 or x = 3/7
<em>Thus, the unknown negative integer is −4.</em>
75n-36=21n^2 rearrange so we have an equation equal to zero...
21n^2-75n+36=0 divide whole equation by 3
7n^2-25n+12=0 now factor...
7n^2-21n-4n+12=0
7n(n-3)-4(n-3)=0
(7n-4)(n-3)=0
Since this is an integer 4/7 is extraneous.
The integer value is 3
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