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tatyana61 [14]
4 years ago
6

A dog is given a dosage of 100 mg of antibiotics. The amount of antibiotics in the dog's bloodstream will decrease by 40% each h

our over the next 8 hours. Which exponential equation models this situation?
Mathematics
1 answer:
jek_recluse [69]4 years ago
5 0

After each hour 60% ( or 0.60) of the drug will be present.

The equation is A = 100(0.6)^t where t = time in hours. (answer)

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May you please answer this question i tried to answer but failed miserably
s2008m [1.1K]

Answer:

I think it is postive

7 0
3 years ago
Solve each equation by factoring.<br> (x – 7)(2x - 3) = 0
Orlov [11]

Answer:

x = 7 and 3/2

Step-by-step explanation:

We can say:

x - 7 = 0 and 2x - 3 = 0

<em>Lets solve for x - 7 = 0 first:</em>

Add 7 to each side of "="

=> <u>x = 7</u>

<em>Now lets solve for 2x - 3 = 0</em>

First add 3 to each side of "="

=> 2x = 3

Now divide each side by 2

<u>=> x = 3/2</u>

Hope this helps!

5 0
3 years ago
A car valued at £18000 at the start of 2017, depreciated in value by 5% each year for 3 years. How much did it lose in value ove
Anna11 [10]

<u>Answer:</u>

The amount lost over the 3 years s 2567.25£  

<u>Explanation:</u>

$\mathrm{F}=\mathrm{I} \times\left(1-\left(\frac{r}{100}\right)\right)^{\mathrm{n}}$

where F = final value after n years

I = initial value of the car in 2017 = £18000 (given)

Since the value is depreciated 5% every year for 3 years,

r = percentage rate of depreciation = 5% (given)

n = 3 years

Substituting these values in formula, we get

$\mathrm{F}=18000 \times\left(1-\frac{5}{100}\right)^{3}$

= $18000 \times\left(\frac{95}{100}\right)^{3}$

 = 15432.75£ which is the value of the car after 3 years

Finally 18000-15432.75 = 2567.25£ is the amount lost over this period.  

6 0
3 years ago
Plz help me with this Plzzzz!!!!
MrRissso [65]
In pretty sure it’s D , making each side equal to 6
4 0
3 years ago
Read 2 more answers
What is the common denominator for 1 2/3 and 3/4
Elena L [17]

Answer:

The answer is 12

Step-by-step explanation:

Multiply 1*3

Add 2 to the number

Change the first number to 5/3

Multiply 3*4

3 0
3 years ago
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