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Svetach [21]
3 years ago
8

If r = 6 units and h = 13 units, what is the volume of the cylinder

Mathematics
1 answer:
Andrews [41]3 years ago
6 0

Answer:

v=1460.26536188 units^3

Step-by-step explanation:

Volume for a cylinder is:

V=πr^2h

Substitute 6 in for r and 13 in for h

V=π(6^2)(13)

V=π(36)(13)

V=π468

v=1460.26536188 units^3

Hope this helps! :)

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Two factors whose product is 84 are 12 and _[blank]_.
djyliett [7]

Answer: 7

Step-by-step explanation:

To solve this problem you must apply the proccedure shown below:

1. You know that a multiplication has the following form:

a*b=c

Where a and b are the factors and c is the product.

2. You know one of the factor, then you can find the second one as following:

12*b=84

b=84/12

b=7

Therefore the answer is 7.

7 0
3 years ago
The quotient of ninety five and a number is what
djyliett [7]
This is how you solve it..
95/n=n
You could put 5 in and get 95/5=19.
8 0
3 years ago
Find the area of this shape.
inessss [21]

Answer:

400-25π

Step-by-step explanation:

The circle and square have a radius of 10. Calculate the are of the circle, then divide by 4. Find the area of the square, then subtract the area from the area of the quarter circle you found previously.

5 0
3 years ago
Find the value of h
slamgirl [31]

Answer:

h = 48

because 32 + 3h + 4 = 180

32 + 4 = 36

36 + 3h - 36 = 180 - 36

3h = 144

3h/3 = 144/3

h = 48

7 0
3 years ago
Given the parabola below, find the endpoints of the latus rectum. (x-2)^2=-20(y+2)
Shtirlitz [24]

Answer:

The endpoints of the latus rectum are (12, -7) and (-8, -7).

Step-by-step explanation:

A parabola with vertex at point C(x, y) = (h,k) and whose axis of symmetry is parallel to the y-axis is defined by the following formula:

(x-h)^{2} = 4\cdot p \cdot (y-k) (1)

Where:

y - Independent variable.

x - Dependent variable.

p - Distance from vertex to the focus.

h, k - Coordinates of the vertex.

The coordinates of the focus are represented by:

F(x,y) = (h, k+p) (2)

The <em>latus rectum</em> is a line segment parallel to the x-axis which contains the focus. If we know that h = 2, k = -2 and p = -5, then the latus rectum is between the following endpoints:

By (2):

F(x,y) = (2, -2-5)

F(x,y) = (2,-7)

By (1):

(x-2)^{2} = -20\cdot (-7+2)

(x-2)^{2} = 100

x - 2 = \pm 10

There are two solutions:

x_{1} = 2 + 10

x_{1} = 12

x_{2} = 2-10

x_{2} = -8

Hence, the endpoints of the latus rectum are (12, -7) and (-8, -7).

4 0
2 years ago
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