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Marizza181 [45]
3 years ago
15

Please help ASAP!!! 20points

Mathematics
2 answers:
STatiana [176]3 years ago
6 0

Answer:

Step-by-step explanation:

Pani-rosa [81]3 years ago
4 0
Question 1

--------------------------------------------------
Formula
--------------------------------------------------
Area of trapezoid  = 1/2 x (a + b) x h

-------------------------
Find area
-------------------------
Area = 1/2 x (14 + 36 ) x 15
Area = 1/2 x 50 x 15
Area = 25 x 15
Area = 375 mm²

--------------------------------------------------
Answer: 375mm² (Answer B)
--------------------------------------------------

Question 2:

-------------------------------------------------
Formula
--------------------------------------------------
Area of trapezoid  = 1/2 x (a + b) x h

--------------------------------------------------
Find area
--------------------------------------------------
Area = 1/2 x (7 + 21 ) x 21
Area = 1/2 x 28 x 21
Area = 14 x 21
Area = 294 m²

--------------------------------------------------
Answer: 294 m² (Answer C)
--------------------------------------------------
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The temperature fell from 0 degrees to 15 1/2 degrees below 0 in 5 3/4 hours. Wen tried to find the change in temperature per ho
iren2701 [21]

Answer:

-62/23 degrees per hour

Step-by-step explanation:

Do this by dividing the total change in temperature (-15 1/2 degrees) by the total elapsed time (5 3/4 hrs):

-31/2 degrees       -62/4 degrees        Note:  convert 31/2 to 62/4

--------------------- = ------------------------ = -62/23 degrees per hour

23/4 hrs                  23/4 hrs


3 0
3 years ago
Help please!! Math, 3 questions.
Papessa [141]

Answer:

Easy so first you have to find the ratio then your done!

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Tan2x=___
SSSSS [86.1K]

Step-by-step explanation:

tan2x = sin2x/cos2x

we know that ,

  • sin2x = 2sinxcosx
  • sin2x = 2sinxcosx cos2x = cos²x - sin²x

Since, tan2x = 2sinx*cosx/cos²x- sin²x

Dividing by cos²x in numerator and denominator.

We get ,

  • tan2x = 2sinx/cosx / 1- sin²x/cos²x

  • Since, we get tan2x= 2tanx/1-tan²x

  • Option (c) is correct option.

  • Hope it will be helpful
7 0
2 years ago
Find the midpoint of the line segment with the given endpoints. 1) (-4, -9), (-6, -6)
weeeeeb [17]

Answer:

The answer is

<h2>( - 5 \: , \:  -  \frac{15}{2} )</h2>

Step-by-step explanation:

The midpoint M of two endpoints of a given line segment can be found by using the formula

<h3>M = ( \frac{x1 + x2}{2}  , \frac{y1 + y2}{2} )</h3>

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-4, -9), (-6, -6)

The midpoint is

<h3>M = ( \frac{ - 4 - 6}{2}  , \:  \frac{ - 9 - 6}{2} ) \\  = ( -  \frac{10}{2} , -  \frac{15}{2} )</h3>

We have the final answer as

<h3>( - 5 \: , \:  -  \frac{15}{2} )</h3>

Hope this helps you

8 0
3 years ago
A builder had been asked to lay an octagonal patio using square paving slabs. To do this, he cuts some of the bricks in half dow
Orlov [11]
Assuming you want an expression for the possible total area of the patio: if "completed" would be a rectangle of dimensions n, m: each must be >=3 to allow for octagonal corners. But each of the 4 corners must be missing, that's diagonals comprising (1/2)a^2, (1/2)b^2, (1/2)c^2, and (1/2)d^2, where a,b,c, and d must be variously limited and co-limited so as to allow at least 1 linear side of the original rectangle to be exposed. So A = (n*m)-(1/2)a^2-(1/2)b^2-(1/2)c^2-(1/2)d^2 as an expression.
Now, imagine replicating your possible (potentially irregular) octagons onto a plane and juxtaposing them so as to create a paved network. What geometric properties might such a network have? You now have a miniscule idea what nature does with silicate networked minerals, except that takes place in 3-D, with tetrahedra of SiO4 .
7 0
3 years ago
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