Melting and pressure.
Weathering and erosion affect any surface rock and make sedimentary rocks, heat and pressure make metamorphic rocks, and melting and cooling make igneous rocks. Melting and pressure is not a step.
Answer:
<h2>99 J</h2>
Explanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 9 × 11
We have the final answer as
<h3>99 J</h3>
Hope this helps you
Answer:

Explanation:
As figure is not given so considering the most relevant diagram for question attached below
We can define Electric field as rate of change of electric potential with respect to space (say x-axis here). It is related in formula as

a) For Region A to B:
As can be seen from figure, point charge moves from 0 to 0.2 along x-axis, the value of electric potential remains constant i.e 5 volts

b) For Region B to C:
As point charge moves from B to C (0.2 to 0.4) along x-axis, the value of electric potential decreases from 5 volts to 3 volts. Electric field induced is:

c) For Region C to D:
As point charge moves from C to D (0.4 to 0.8) along x-axis, the value of electric potential decreases from 3 volts to 1 volt. Electric field induced is:

For Information:
Unit of Electric field is V/m or N/C
Answer:
Explanation: This is done using the equation:

Because the Radius is a know value. We have the following.

Which is:
4188.7902 mm
Answer:
Correct answer: m = 1,160 kg
Explanation:
Given:
P = 104 hp = 77.48 kW = 77.48 · 10³ W
V₁ = 21 m/s Initial speed (velocity)
V₂ = 29 m/s Final speed (velocity)
t = 3 seconds The time interval during which the work was performed
m = ?
The formula for calculating power is:
P = A / Δt
Since work is a measure of energy change in this case kinetic:
P = ΔEk / Δt = (Ek₂ - Ek₁) / Δt = (m V₂²/ 2 - m V₁²/ 2) / Δt
P = m · (V₂² - V₁²) / 2 · Δt ⇒ m = (2 · P · Δt) / (V₂² - V₁²)
m = (2 · 77.48 · 10³ · 3) / (29² - 21²) = 464.88 · 10³ / (841 - 441)
m = 464.88 · 10³ / 400 = 1.16 · 10³ = 1,160 kg
m = 1,160 kg
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