Answer:
Hello your question has some missing part attached below is the missing part
How much work is done by the cog system on the cars?
<em>answer</em> : 2.053 * 10^7 J
Explanation:
Total weight of car ( wT ) = 5900 * 29 = 171100 N
mass of car ( mT ) = wT / g = 171100 / 9.81 = 17459.18 kg
Hence <u>work done by the cog system on the cars</u>
W = ( KE
+ PE ) - ( KE
+ PE )
= ( 1/2 mv^2 + mgh ) - ( 0 )
= ( 1/2 * 17459.18 * 0.50^2) + ( 17459.18 * 9.81 * 120 )
= 2.053 * 10^7 J
Answer:
See explanation below
Explanation:
In this case, you want to know if you put an object between these forces, which direction would go.
To know this, we need to calculate the moment of an object, which is defined as the product of a force and it's distance. In other words:
M = F * d (1)
And, in order to reach equilibrium the force will exert a direction in clockwise or anticlosewise, and these moments, should be even:
anticlockwise moment = clockwise moment.
The clockwise would be the forces to the right, and anticlock would the only force to the left of the axle.
Clockwise moment = (10 * 0.8) + (25 * 2.6) = 73 Ns
Anticlockwise moment = 34 * 3.5 = 119 Ns.
As we can see, the moment in the anticlockwise is higher than the actual clockwise moment, therefore, we can assume that the object will move anticlockwise, or simply move to the left.
Hope this helps
Light<span> refracts whenever it </span>travels<span> at an angle into a substance with a </span>different<span>refractive index (optical density). This change of direction is </span>caused<span> by a change in speed. For example, when </span>light travels<span> from air into water, it slows down, causing it to continue to travel at a </span>different<span> angle or direction.</span>
Because the move through water
Answer: Choose the normal force acting between the object and the ground. Let's assume a normal force of 250 N.
Determine the friction coefficient.
Multiply these values by each other: 250 N * 0.13 = 32.5 N .
You just found the force of friction!
Explanation:
