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Musya8 [376]
3 years ago
14

What is the energy of a 4kg apple that is sitting on a 2 m high tree branch?

Physics
1 answer:
miv72 [106K]3 years ago
8 0

78.4 joules is the energy of a 4 kg apple that is sitting on a 2 m high tree branch.

<u>Explanation: </u>

When an apple falls to the ground from a tree, its positional energy (stored as potential gravitational energy) turns into kinetic energy, during a fall. Chemical potential energy is chemical energy because it is food and potential energy as it can still have ability to move. So, in the given case, kinetic energy is zero.

To find potential energy, the formula would be

             \text { potential energy }(P . E)=m \times g \times h

Where, given

m – Mass – 4 kg

g-\text { Earth'sgravity }-9.8 \mathrm{m} / \mathrm{s}^{2} (Known value)

h – Height -  2 m

Substitute these values, we get

                  P . E=4 \times 9.8 \times 2=78.4 \text { joules }

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Object A is moving due east, while object B is moving due north. They collide and stick together in a completely inelastic colli
Pie

Answer:

a)  v = 3,843 m / s, b)  46.7º  North- East

Explanation:

Moment is a vector quantity, so one of the best ways to solve this problem is to solve each component separately.

The system is formed by the two vehicles so that the moment is preserved during the crash

Direction to the East    

initial instant. Before the crash

          p₀ = mₐ vₐ₀

final insttne. After the crash

          p_f = (mₐ + m_b) vₓ

         p₀ = p_f

         mₐ vₐ₀ = (mₐ + m_b) vₓ

         vₓ = \frac{m_a}{m_a + m_b} \ v_{ao}

let's calculate

          vₓ = \frac{16.7}{16.7 + 29.3} \ 7.26

          vₓ = 2,636 m / s

direction north

initial   p₀ = m_b v_{bo}

final     p_f = (mₐ + m_b) v_y

          p₀ = p_f

          m_b v_{bo} = (mₐ + m_b) v_y

          v_y = \frac{m_b}{m_a+m_b} \ v_{bo}

let's calculate

          v_y = \frac{29.3}{16.7 + 29.3} \ 4.39

          v_y = 2.796 m / s

the final speed of the two two vehicles is

          v = (2,636 i ^ + 2,796 j ^) m / s

a) the magnitude of the velocity

let's use the Pythagorean theorem

       v = \sqrt{v_x^2 + v_y^2}

      v = \sqrt{2.636^2 + 2.796^2}

      v = 3,843 m / s

b) let's use trigonometry to find the direction

      tan θ = v_y / vₓ

      θ = tan⁻¹ v_y / vₓ

      θ = tan⁻¹ (2,796 / 2,636)

      θ = 46.7º

This direction is 46.7º  North East

7 0
3 years ago
A golfer strikes a 0.059-kg golf ball with a force of 290 N. If the ball moves with a velocity of 69 m/s,
Ymorist [56]

Answer:

0.014s

Explanation:

Given parameters:

mass of golf ball  = 0.059kg

force applied  = 290N

velocity = 69m/s

initial velocity  = 0m/s

Unknown:

Time of contact  = ?

Solution;

We know that momentum is the quantity of motion of body possess;

  Momentum  = mass x velocity

  Momentum  = 0.059 x 69  = 4.1kgm/s

Also; impulse is the effect of the force acting on a body;

  impulse  = force x time  = momentum

  So;

            Force x time  = momentum

                  Time  = \frac{momentum}{force }    = \frac{4.1}{290}    = 0.014s

 

 

4 0
3 years ago
Which of the following is NOT a
Liula [17]

Answer:B

Explanation:

6 0
4 years ago
Read 2 more answers
Is It true that if you drop a heavy object and a lighter object at the same time, they will both drop at the same time due to gr
valkas [14]

Answer:

\huge\boxed{True.}

Explanation:

This is true because gravity is independent of mass. Whether it's a heavy or a light object, when dropped, they both will hit the ground at the same time. The reason is that gravity does not depend on mass.

Hope this helped!

<h2>~AnonymousHelper1807</h2>
4 0
3 years ago
True or False <br>One of the objections to the solar nebula theory is the angular momentum problem.
KengaRu [80]

Answer:

False, the angular momentum problem is not one of the objections to the solar nebular theory.

5 0
3 years ago
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