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IgorLugansk [536]
3 years ago
7

Which of the following is equivalent to the expression 4-x

Mathematics
1 answer:
maks197457 [2]3 years ago
3 0
(4 minus x) is the correct one.
You might be interested in
107 = 7 - 2(7b - 1) what does b equal?
topjm [15]

107 = 7 -2 (7b - 1)

First, distribute -2 to all terms within the parenthesis

-2(7b - 1) = -14b + 2

107 = 7 -14b + 2

Combine like terms

107 = -14b (+7 + 2)

107 = -14b + 9

Isolate the b. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

Subtract 9 from both sides

107 (-9) = -14b + 9 (-9)

107 - 9 = -14b

98 = -14b

Isolate the b. Divide -14 from both sides

(98)/-14 = (-14b)/-14

98/-14 = b

b = −7

-7 is your answer

hope this helps

5 0
3 years ago
Compare 0.48 and 6/15
Margarita [4]
You could write 6/15 as a decimal 0.40.
Therefore .48>.40
6 0
3 years ago
Read 2 more answers
What is the slope of the line that passes through the points (2,3) and (-2,6)?
Kobotan [32]

Answer:

-3/4

Step-by-step explanation:

To find the slope of the line, use the slope formula:

m = \frac{y_2-y_1}{x_2-x_1} = \frac{6-3}{-2-2} =\frac{3}{-2+-2}=\frac{3}{-4}

The slope of the line is -3/4.

3 0
3 years ago
Or yk dont answer my question thats coo :/
san4es73 [151]

Answer:

whats the question i might be able to help

Step-by-step explanation:

:)))))))

6 0
3 years ago
Pre-image point N(6, -3) was dilated to point N'(2, -1). What was the scale factor used?
blagie [28]

Question 1

Let the scale factor be k.

Then, we have the mapping

N(6,-3)\to N'(6k,-3k)

This implies that:

(6k,-3k)=(2,-1)

We equate any corresponding component find the value of the scale factor k.

6k=2

k=\frac{2}{6}

k=\frac{1}{3}

Hence the scale factor is  \frac{1}{3}

Question 2:

The midpoint of any two points can be calculated using the formula;

(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

We want to find the midpoint of (-8, 5) and (2, -2).

(\frac{-8+2}{2}, \frac{5+-2}{2})

(\frac{-6}{2}, \frac{3}{2})

The midpoint is:

(-3, \frac{3}{2})

5 0
3 years ago
Read 2 more answers
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