we know that
The probability that "at least one" is the probability of exactly one, exactly 2, exactly 3, 4 and 5 contain salmonella.
The easiest way to solve this is to recognise that "at least one" is ALL 100% of the possibilities EXCEPT that none have salmonella.
If the probability that any one egg has 1/6 chance of salmonella
then
the probability that any one egg will not have salmonella = 5/6.
Therefore
for all 5 to not have salmonella
= (5/6)^5 = 3125 / 7776
= 0.401877 = 0.40 to 2 decimal places
REMEMBER this is the probability that NONE have salmonella
Therefore
the probability that at least one does = 1 - 0.40
= 0.60
the answer is
0.60 or 60%
Answer:
80 :D!
Step-by-step explanation:
30 + (6 x 7) + 8
30 + 42 + 8
72 + 8
= 80
Hope this helps! Brainliest plz?
Answer:
The number of bananas that Emily bought was 6 and the number of peaches that Emily bought was 8
Step-by-step explanation:
<u><em>The complete question is</em></u>
Emily and her children went into a grocery store and she bought $20.80 worth of bananas and peaches. Each banana costs $0.80 and each peach costs $2. She bought a total of 14 peaches and bananas altogether. Determine the number of peaches and the number of bananas that Emily bought
Let
x ----> the number of bananas that Emily bought
y ----> the number of peaches that Emily bought
we know that
She bought a total of 14 bananas and peaches altogether
so
-----> equation A
She bought $20.80 worth of bananas and peaches
so
-----> equation B
Solve the system by graphing
Remember that the solution is the intersection point both graphs
using a graphing tool
The solution is the point (6,8)
see the attached figure
therefore
The number of bananas that Emily bought was 6 and the number of peaches that Emily bought was 8
i think the answer would be C