Answer:
Step-by-step explanation:
30. Given: rectangles QRST and RKST
Prove: ΔQSK is isosceles
An isosceles triangle is a triangle which has two sides and two angles to be equal.
Thus,
From rectangle QRST, the diagonals of rectangles are similar.
i.e RT ≅ QS (diagonal property)
Also, RT ≅ SK (opposite sides of rectangle RKST)
Thus,
RT ≅ QS ≅ SK
Therefore,
ΔQSK is an isosceles triangle.
31. Given: Rectangles QRST, RKST and JQST
Prove: JT ≅ KS
From rectangle QRST, the diagonals of rectangles are similar.
i.e RT ≅ QS (diagonal property)
But,
JT // QS and RT // KS
Thus,
JT ≅ QS (opposite sides of rectangle JQST)
also,
RT ≅ KS (opposite sides of rectangle RKST)
So that,
JT ≅ QS ≅ RT ≅ KS
Therefore,
JT ≅ KS
Answer:
4 units
Step-by-step explanation:
according to question:
perimeter of square = 16 units
4a = 16
where a is the side length
a = 16/4
= 4 units
You just have to plug in each value of x into the equation of 3x^2. Since y is a function, it is also written as f(x)
Yes, The line will be parallel because when the alternate interior angle or exterior angle, co enterior angle etc. are equal then the line will be parallel
Answer:
x = 2
Step-by-step explanation:
3x - 1 = 5
First, add 1 onto both sides. (When doing these type of questions you must do the inverse!)
3x = 6
Divide by 3 on both sides to get x.
x = 2
Hope this helps and I hope you have a good day!
