Answer:
Bet
Step-by-step explanation:
It’s a simple one to write. There are many trios of integers (x,y,z) that satisfy x²+y²=z². These are known as the Pythagorean Triples, like (3,4,5) and (5,12,13). Now, do any trios (x,y,z) satisfy x³+y³=z³? The answer is no, and that’s Fermat’s Last Theorem.
On the surface, it seems easy. Can you think of the integers for x, y, and z so that x³+y³+z³=8? Sure. One answer is x = 1, y = -1, and z = 2. But what about the integers for x, y, and z so that x³+y³+z³=42?
That turned out to be much harder—as in, no one was able to solve for those integers for 65 years until a supercomputer finally came up with the solution to 42. (For the record: x = -80538738812075974, y = 80435758145817515, and z = 12602123297335631. Obviously.)
Answer: Expression represents the number of text messages you sent on Tuesday = 2x
Expression represents the number of text messages you sent on Wednesday = 12+2x
Expression represents the number of text messages you sent on Thursday = x+6
Step-by-step explanation:
Given:
Number of text messages sent on Monday = x
On Tuesday, Number of text messages sent = 2 (Number of messages sent on Monday)
= 2 x
On Wednesday, Number of text messages sent = 12+ (Number of messages sent on Tuesday)
= 12 +2x
On Thursday, Number of text messages sent = 
= x+6
Expression represents the number of text messages you sent on Tuesday = 2x
Expression represents the number of text messages you sent on Wednesday = 12+2x
Expression represents the number of text messages you sent on Thursday = x+6
Answer:
y = 0.35x + 2.5
Step-by-step explanation:
¡Hola!
Your answer to the question is 10/12.
Step-by-step explanation:
By using the y^2-y^1/x^2-x^1
12-2= 10
16-4= 12
So your answer is 10/12.
Hope this Helps!
A suitable probability calculator can tell you the probability is about 6.7%.
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The standard deviation of the distribution of sample means is the population standard deviation (6) divided by the square root of the sample size (√144=12). Thus, your threshold is about (19.25-20)/(6/12) = -1.5 standard deviations from the mean.