Solve the equation using the method of completing the square. A. B. C. D.
2 answers:
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**y=x+2
when x=0,y=2; A(0,2)
when x=1,y=3; B(1,3)
**y=-x+8
when x=0,y=8; C(0,8)
when x=5,y=-3; D(5,-3)
The solution from the graph is S(2,4).
when x=0,y=2; A(0,2)
when x=1,y=3; B(1,3)
**y=-x+8
when x=0,y=8; C(0,8)
when x=5,y=-3; D(5,-3)
The solution from the graph is S(2,4).
The cost of children’s ticket is $ 5
<h3><u>Solution:</u></h3>Let "c" be the cost of one children ticket
Let "a" be the cost of one adult ticket
Given that adult ticket to a museum costs 3$ more than a children’s ticket
<em>Cost of one adult ticket = 3 + cost of one children ticket</em>
a = 3 + c ------ eqn 1
<em><u>Given that 200 adult tickets and 100 children tickets are sold, the total revenue is $2100</u></em>
200 adult tickets x cost of one adult ticket + 100 children tickets x cost of one children ticket = 2100
200a + 100c = 2100 ------ eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>
Substitute eqn 1 in eqn 2
200(3 + c) + 100c = 2100
600 + 200c + 100c = 2100
600 + 300c = 2100
300c = 1500
<h3>c = 5</h3>Thus the cost of children’s ticket is $ 5