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Mrac [35]
4 years ago
13

An engineer must design a runway to accommodate airplanes that must reach a ground speed velocity of 61 m/s before they can take

off. These planes are capable of accelerating at a rate of 2.5 m/s2.
a.) How long will it take the planes to reach takeoff speed?
b.)What must be the minimum length of the runway?
Physics
1 answer:
Alla [95]4 years ago
5 0

You are correct that a twin-engine jet will have an average takeoff run of 30 – 35 seconds, good observation. It will vary depending on the altitude of the airport, the weight of the airplane and the outside temperature. The lift-off speed (VR) will also vary depending on the weight

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A 0.75-kg ball falls vertically downward from a height of 55.0 m and rebounds upward. if the ball reaches a height of 30.0 m and
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Impuls I is given by:
I = \delta mv = |F|t
where \delta mv is the change in momentum, |F| is the average force and t is the time.

Solve the equation for the force F:
|F| = \frac{\delta mv}{t} = \frac{m(v_f - v_i)}{t}

Energy should be conserved, so the velocities will be:
\frac{1}{2}mv^2 = mgh \\ v = \sqrt{2gh}

Combining both equations:
|F| =  \frac{m( \sqrt{2g(h_f + h_i)} )}{t}
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4 0
4 years ago
What happens to a catalyst after a chemical reaction has occurred
jenyasd209 [6]
It goes away and goes off to catalyze more things. Imagine it like the priest of a wedding. S/He's just catalyzing the bond between two entities, and s/he will continue to do that, not having anything to do with the bond past its creation.
3 0
4 years ago
When you stay in your mothers stomach for 9 months, when you are born why aren't you already 9 months old ?
Lemur [1.5K]
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3 0
4 years ago
Two Carnot heat engines are operating in series such that the heat sink of the first engine serves as the heat source of the sec
kakasveta [241]

Answer:

the temperature of the intermediate reservoir is 624.5 K

Explanation:

Given the data in the question  

The two Carnot heat engines are operating in series;

[ T_H ]

  ↓

((1)) ⇒ W_{out

  ↓

[ T_M ]

   ↓

 ((2)) ⇒ W_{out

[ T_L ]

The maximum possible efficiency for any heat engine is the Carnot efficiency;

η_{rev = 1 - \frac{T_L}{T_H}

the thermal efficiencies if both engines are the same will be;

η_A = η_B

1 -  \frac{T_M}{T_H} = 1 - \frac{T_L}{T_M}

1 - 1 -  \frac{T_M}{T_H} = - \frac{T_L}{T_M}

-  \frac{T_M}{T_H} = - \frac{T_L}{T_M}

\frac{T_M}{T_H} =  \frac{T_L}{T_M}

T_M² = T_L × T_H

T_M = √(T_L × T_H)

source temperature of the first engine T_H = 1300 K

sink temperature of the second engine T_L = 300 K

we substitute

T_M = √(300 × 1300)

T_M = √390000

T_M = 624.4998 K ≈ 624.5 K

Therefore, the temperature of the intermediate reservoir is 624.5 K

4 0
3 years ago
A measurement has high<br> when it is very close to the<br> true value?
jarptica [38.1K]

Answer:

Accuracy

Explanation:

Accuracy means making measurements that are close to the value precision means making measurement that are close in value to eachother but not necessarily close to the true value.

I hope this helps! If not sorry.

7 0
3 years ago
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