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alexira [117]
3 years ago
15

initially, only a and b are present, each at 2.00 m. what is the final concentration of a once equilibrium is reached?

Business
1 answer:
nataly862011 [7]3 years ago
4 0
 <span>The "REVERSIBLE" chemical reaction- 
A + B <--> C + D 
Kc = [C][D] / [A][B] = 6.8 
Concentration at the start and after equilibrium- 
[A] = 2.00 M --> (2.00 - X) M 
[B] = 2.00 M --> (2.00 - X) M 
[C] = 0.00 M --> X M 
[D] = 0.00 M --> X M 
6.8 = X^2 / (2.00 - X)^2 
take the square root of both sides- 
2.6077 = X / (2.00 - X) 
5.2154 - 2.6077 X = X 
5.2154 = 3.6077 X 
X = 1.4456 
at equilibrium- 
[A] = 0.55 M 
[B] = 0.55 M 
[C] = 1.45 M 
[D] = 1.45 M</span>
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2 years ago
2. Fiscal policy Suppose a hypothetical economy is currently in a situation of deficient aggregate demand of $32 billion. Four e
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Answer:

For the Economist A the spending multiplier  is = 8, the tax multiplier = 4, the increase in spending is = $4 billion, the tax cut is = $8 billion.

For the Economist B, the spending multiplier is =4, the tax multiplier = 2, the increase in spending is = $8 billion, the tax cut is = $16 billion.

Explanation:

Solution

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(1)The Economist A

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