Answer:
(1) <em>C</em> C3H7OH = 9.200 M
(2) <em>C</em> C3H7OH = 11.647 m
Explanation:
mixture:
∴ 70% = (g C3H7OH/g mix)×100
∴ 30% = (gH2O/g mix)×100
∴ δ mix = 0.79 g/mL
assuming:
⇒ V mix = (100g)×(mL/0.79g) = 126.582 mL mix = 0.1266 L mix
⇒ g C3H7OH = 70g
⇒ g H2O = 30g
∴ Mw C3H7OH = 60.1 g/mol
∴ Mw H2O = 18 g/mol
(1) Molar concentration (M):
⇒ <em>C</em> C3H7OH = ((70 g)(mol/60.1 g))/(0.1266L) = 9.200 M
(2) molal concentration (m):
⇒ <em>C </em>C3H7OH = ((70 g)(mol/60.1g))/(0.100 Kg) = 11.647 m
Answer:
Answer is in the explanation.
Explanation:
The principal difference between percent recovery and percent yield is that the second involves a chemical reaction whereas the first is more about a purification process.
Thus, percent yield is defined as the ratio between amount of product and theoretical yield.
Percent recovery is the ratio between final amount of purified substance and initial amount of substance.
I hope it helps!
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The percent by mass of calcium hydroxide in the solution : 15.41%
<h3>Further explanation</h3>
The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight/volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.
Mass of solute (Ca(OH₂-Calcium hydroxide) : 28.5
Mass of solution = 185 g
