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m_a_m_a [10]
2 years ago
13

What are valence electrons and why are they so important in chemistry?

Chemistry
2 answers:
natka813 [3]2 years ago
7 0
Valence electrons is an electron that can participate in the formation of a chemical bond.Also, valence electrons have the ability to absord or release energy in the form of a photon. Valence electrons are in the energy level that is farthest aways from the nucleus. The valence electrons are the ones, that in a chemical reaction, are gained, lost or shared.

stealth61 [152]2 years ago
3 0

valance electrons that reside in the outermost shell of an atom in the highest energy level. They are important to atoms because the fewer valence electrons that the atom holds, it becomes less stable.

I take honors chemistry I hope this helps.

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If a radioisotope has a half-life of 4 years, how much remains of a starting amount of 40 grams after 16 years have passed?
Gwar [14]

Answer:

only 2.5 grams will be present after 16 years have passed

5 0
3 years ago
What determines the ending units of a stoichiometry problem?
kicyunya [14]

Answer:

1.Write the balanced chemical equation.

2.Convert the units of the given substance (A) to moles.

3.Use the mole ratio to calculate the moles of wanted substance (B).

4.Convert moles of the wanted substance to the desired units.

Explanation:

4 0
2 years ago
2.What is the chemical formula<br> for ammonium nitrite
jeyben [28]

Answer:

NH4NO3

Explanation:

I hope this helps you:)

5 0
2 years ago
How many moles are there in 990 grams of sugar, C12H22011? (Sig Figs, do not
Nitella [24]

Answer:

Number of moles = 2.89 mol

Explanation:

Given data:

Number of moles of sugar  = ?

Mass of sugar = 990 g

Solution:

Formula:

Number of moles = mass/molar mass

Molar mass of C₁₂H₂₂O₁₁:

12× 12 + 22×1.008 + 16×11 = 342.2 g/mol

Number of moles = 990 g / 342.2 g/mol

Number of moles = 2.89 mol

6 0
3 years ago
If the initial [NO2] is 0.260 M, it will take ________ s for the concentration to drop to 0.150 M. If the initial is 0.260 , it
Nitella [24]

The question is incomplete, here is the complete question:

At elevated temperature, nitrogen dioxide decomposes to nitrogen oxide and oxygen gas

NO_2\rightarrow NO+\frac{1}{2}O_2

The reaction is second order for NO_2 with a rate constant of 0.543M^{-1}s^{-1} at 300°C. If the initial [NO₂] is 0.260 M, it will take ________ s for the concentration to drop to 0.150 M

a) 1.01    b) 5.19     c) 0.299      d) 0.0880     e) 3.34

<u>Answer:</u> The time taken is 5.19 seconds

<u>Explanation:</u>

The integrated rate law equation for second order reaction follows:

k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)

where,

k = rate constant = 0.543M^{-1}s^{-1}

t = time taken  = ?

[A] = concentration of substance after time 't' = 0.150 M

[A]_o = Initial concentration = 0.260 M

Putting values in above equation, we get:

0.543=\frac{1}{t}\left (\frac{1}{(0.150)}-\frac{1}{(0.260)}\right)\\\\t=5.19s

Hence, the time taken is 5.19 seconds

6 0
3 years ago
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