3 years ago

What is the amswer to -4k-2(k-3)=-6k+8

Mathematics

1 answer:

SashulF [63]3 years ago

4 0

Answer:

k = 1/2

Step-by-step explanation:

-4k-2(k)-2(-3)=-6k+8

-4k-2k+6=-6k+8

-2k+6=-6k+8

4k+6=8

4k=2

4k/4= 2/4

k=1/2

You might be interested in

Solve the following system of equations. 2x + 5y = 19 x - 2y = - 4

garri49 [273]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The figure below shows the front side of a purse in the shape of a trapezoid. Find the area of the trapezoid.

loris [4]

Answer:

110 in²

Step-by-step explanation:

Area of trapezoid formula:

A = (b₁ + b₂)h/2

Substitute the values on the sketch and find the area:

A = (9 + 13)*10/2 = 110 in²

8 0

2 years ago

Find the angle between the given vector in degrees. u=<6, 4>, v=<7, 5> HELPPPPPPPPPP

Paladinen [302]

Recall that

$\vec a\cdot\vec b=\|\vec a\|\|\vec b\|\cos\theta$

where $\theta$ is the angle between the vectors $\vec a,\vec b$ whose magnitudes are $\|\vec a\|,\|\vec b\|$ , respectively.

We have

$\langle6,4\rangle\cdot\langle7,5\rangle=\sqrt{6^2+4^2}\sqrt{7^2+5^2}\cos\theta$

$\cos\theta=\dfrac{31}{\sqrt{962}}\implies\theta\approx88.2^\circ$

7 0

2 years ago

Whoever can answer 11-2 in PEDMAS form pls do it.

butalik [34]

Answer:

Step-by-step explanation:

11 - 2 = 9

3 0

2 years ago

The image of a point is B'(-4, 11). A 180° clockwise rotation was performed to get this image. What were the coordinates of the

Musya8 [376]

I think it would be 4 11

4 0

3 years ago

Read 2 more answers