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ikadub [295]
2 years ago
9

Jimmy spent $121.60 on shirts. Tee shirts cost $9.10 and long sleeve shirts cost $14.20. If he bought a total of 10, how many of

each kind did he buy? Please answer
Mathematics
1 answer:
Svetlanka [38]2 years ago
7 0
The answer my friend is 6 long shirts and 4 teeny shirts
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dalvyx [7]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Separate 60 into two parts so that 3 times the smaller added to 6 more than 6 times the smaller = 60.
Nikolay [14]
I believe your answer is 6x10
8 0
3 years ago
margo borrows $900.00 and must pay it back with 6% interest after 7 months. what is the total amount margo will pay back ?
ozzi

Answer:

$954

Step-by-step explanation:

6% = 0.06

Adding 1 to the interest makes it so it’s added to the original amount.

$900 x 1.06 = $954

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2 years ago
Solve for a:<br>9+2a = -3-4a​
lubasha [3.4K]

Answer:

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Step-by-step explanation:

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5 0
2 years ago
Almost all medical schools in the United States require students to take the Medical College Admission Test (MCAT). To estimate
Leviafan [203]

Answer:

Probability of having student's score between 505 and 515 is 0.36

Given that z-scores are rounded to two decimals using Standard Normal Distribution Table

Step-by-step explanation:

As we know from normal distribution: z(x) = (x - Mu)/SD

where x = targeted value; Mu = Mean of Normal Distribution; SD = Standard Deviation of Normal Distribution

Therefore using given data: Mu (Mean) = 510, SD = 10.4 we have z(x) by using z(x) = (x - Mu)/SD as under:

In our case, we have x = 505 & 515

Approach 1 using Standard Normal Distribution Table:

z for x=505: z(505) = (505-510)/10.4 gives us z(505) = -0.48

z for x=515: z(515) = (515-510)/10.4 gives us z(515) = 0.48

Afterwards using Normal Distribution Tables and rounding the values to two decimals we find the probabilities as under:

P(505) using z(505) = 0.32

Similarly we have:

P(515) using z(515) = 0.68

Now we may find the probability of student's score between 505 and 515 using:

P(505 < x < 515) = P(515)-P(505) = 0.68 - 0.32 = 0.36

PS: The standard normal distribution table is being attached for reference.

Approach 2 using Excel or Google Sheets:

P(x) = norm.dist(x,Mean,SD,Commutative)

P(505) = norm.dist(505,510,10.4,1)

P(515) = norm.dist(515,510,10.4,1)

Probability of student's score between 505 and 515= P(515) - P(505) = 0.36

Download pdf
6 0
3 years ago
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