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igor_vitrenko [27]
3 years ago
14

A rectangle has a length of 6x units and a width of 8 units

Mathematics
2 answers:
noname [10]3 years ago
7 0
6 times 8 is 48  

48 is the answerz
xz_007 [3.2K]3 years ago
3 0
48 is the answer to 6×8
You might be interested in
Days/ cost to rent a truck 1/34 2/50 3/66 4/82 A/ C=16d B/ C= 16d + 18 C/ C= 16d + 16 D/ C=18d + 16
Mamont248 [21]
Use the given information as (x, y) points.
You have
(1, 34)
(2, 50)
(3, 66)
(4, 82)
The difference between renting for 1 day and 2 days is 50 - 34 = 16.
The difference between renting for 2 days and 3 days is 66 - 50 = 16
The difference between renting for 3 days and 4 days is 82 - 66 = 16
For each day you rent you pay $16.
Now look at renting for 1 day.
The rental for 1 day is $16, but for 1 day you pay $34.
$34 - $16 = $18
There is an extra $18 in the rental for every day. The $18 is fixed.
That means, to rent a truck, you must pay a fixed amount of $18 plus $16 per day.

total cost = daily cost + fixed cost
total cost =       16d    +      16
c = 16d + 18
3 0
3 years ago
Read 2 more answers
What is the initial value of the equation shown?
hodyreva [135]
C. −6, is the best option
7 0
3 years ago
Read 2 more answers
What is 42÷(15-2 by the power of 3<br><img src="https://tex.z-dn.net/?f=42%20%5Cdiv%2815%20-%202%20%7B%7D%5E%7B3%7D%20%29" id="T
tigry1 [53]
Answer: 6

Explanation: first you have to get rid of the 2 power of 3, 2 x 2 x 2 is 8. Then 15-8=7. Then 42➗7 is 6
4 0
4 years ago
Solve and in standard form please. you must add. this is from khan academy
Sindrei [870]
We are asked to sum the two trinomials (-4f^3-5f+16)+(4f^2-f+9). We can start by using the distributive property to remove the parenthesis, giving us -4f^3-5f+16+4f^2-f+9. Next, when we combine like terms, we get \boxed{-4f^3+4f^2-6f+25}. Hope this helped!
8 0
3 years ago
Read 2 more answers
Help me pls!!!!!!!!!
Dominik [7]

Answer:

x^2+18=-9x : x = -3, x = -6

Step-by-step explanation:

x^2+18=-9x

Add 9x to both sides:

x^2+18+9x=-9x+9x

Simplify:

x^2+9x+18=0

Solve with the quadratic formula:

For a quadratic equation of the form ax^2+bx+c=0 the solutions are:

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

For a=1,\:b=9,\:c=18:\quad x_{1,\:2}=\frac{-9\pm \sqrt{9^2-4\cdot \:1\cdot \:18}}{2\cdot \:1}

x =\frac{-9 + \sqrt{9^2-4\cdot \:1\cdot \:18}}{2\cdot \:1} : -3

x =\frac{-9 - \sqrt{9^2-4\cdot \:1\cdot \:18}}{2\cdot \:1} : -6

The solution to the quadratic equation are:

x=-3,\:x=-6

Hope I helped. If so, may I get brainliest and a thanks?

Thank you, have a good day!

6 0
3 years ago
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