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igor_vitrenko [27]
3 years ago
14

A rectangle has a length of 6x units and a width of 8 units

Mathematics
2 answers:
noname [10]3 years ago
7 0
6 times 8 is 48  

48 is the answerz
xz_007 [3.2K]3 years ago
3 0
48 is the answer to 6×8
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BEEEP Hhh, Math sucks ;-;
Alex

Answer:

A is the answer.

Step-by-step explanation:

C=2πr

/2π /2π

C/2π=r

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3 years ago
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The point which divides the line segment joining the points (2, -6) and (3, 4) in the ratio 1 : 2 internally lies in the
ludmilkaskok [199]
According to someone else on brainly it says he point which divides the line segment joining the points 8,-9 and 2,3 in the ratio 1:2 internally lies in the quadrant
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The recursive function for a sequence is given below.
masya89 [10]

Answer:

f(5) = 3200

Step-by-step explanation:

Using the recursive formula to generate the terms, that is

f(2) = 2 × f(1) = 2 × 200 = 400

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3 years ago
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Use the distributive property to solve the equation -4(x+3)=8
algol [13]

Answer:

x=-5

Step-by-step explanation:

-4(x+3)=8\\\\(-4)(x)+(-4)(3)=8\\\\-4x+(-12)=8\\\\-4x-12=8\\\\-4x-12+12=8+12\\\\-4x=20\\\\\frac{-4x}{-4}=\frac{20}{-4}\\\\x=-5

7 0
2 years ago
What are the zeros of the quadratic function f(x) = 6x2 – 24x + 1?<br><br> fast please
xxTIMURxx [149]

Answer:      6(x²-4x+4-4)+1=0, 6(x-2)²-24+1=0, 6(x-2)²=23, x-2=±√(23/6), x=2±√(23/6)=2±1.95789, so x=3.95789 or 0.04211 approx. these are the zeros.

step by step explanation:

\boxed{\boxed{\dfrac{12+\sqrt{138}}{6},\ \dfrac{12-\sqrt{138}}{6}}}

Solution-

The quadratic function is,

6x^2-24x + 1

a = 6, b = -24, c = 1

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

=\dfrac{-(-24)\pm \sqrt{-24^2-4\cdot 6\cdot 1}}{2\cdot 6}

=\dfrac{24\pm \sqrt{576-24}}{12}

=\dfrac{24\pm \sqrt{552}}{12}

=\dfrac{24\pm 2\sqrt{138}}{12}

=\dfrac{12\pm \sqrt{138}}{6}

=\dfrac{12+\sqrt{138}}{6},\ \dfrac{12-\sqrt{138}}{6}

4 0
4 years ago
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