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kumpel [21]
2 years ago
14

What is the sum of 10.8 + 42 4/5? A) 52 1/5 B) 52 3/5 C) 53 1/5 D) 53 3/5

Mathematics
1 answer:
ira [324]2 years ago
6 0
10.8 + 42 4/5 would be D) 53 3/5.
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8 0
3 years ago
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Help me on the last question please asap
bogdanovich [222]
Is the question your asking the one at the bottom
7 0
3 years ago
Help ASAP giving BRAINLIEST! Am i correct?
murzikaleks [220]

Answer:

The answer is yes

Step-by-step explanation:

x-7 > 27

x> 27 +7

x > 34

3 0
3 years ago
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a student takes two subjects A and B. Know that the probability of passing subjects A and B is 0.8 and 0.7 respectively. If you
aniked [119]

Answer:

0.64 = 64% probability that the student passes both subjects.

0.86 = 86% probability that the student passes at least one of the two subjects

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Passing subject A

Event B: Passing subject B

The probability of passing subject A is 0.8.

This means that P(A) = 0.8

If you have passed subject A, the probability of passing subject B is 0.8.

This means that P(B|A) = 0.8

Find the probability that the student passes both subjects?

This is P(A \cap B). So

P(B|A) = \frac{P(A \cap B)}{P(A)}

P(A \cap B) = P(B|A)P(A) = 0.8*0.8 = 0.64

0.64 = 64% probability that the student passes both subjects.

Find the probability that the student passes at least one of the two subjects

This is:

p = P(A) + P(B) - P(A \cap B)

Considering P(B) = 0.7, we have that:

p = P(A) + P(B) - P(A \cap B) = 0.8 + 0.7 - 0.64 = 0.86

0.86 = 86% probability that the student passes at least one of the two subjects

3 0
3 years ago
Which is the equation of a line with a slope of -1/3 and a y-intercept at (0,1)?
Nutka1998 [239]

Answer:

The answer is

\huge \boxed{y =  -  \frac{1}{3}x + 1 }

Step-by-step explanation:

To find an equation of a line given the slope and a point we use the formula

y -  y_1 = m(x -  x_1)

where

m is the slope

( x1 , y1) is the point

From the question the point is (0,1) and slope - 1/3

The equation is

y - 1 =  -  \frac{1}{3}(x - 0) \\ y - 1 =  -  \frac{1}{3} x

We have the final answer as

y =  -  \frac{1}{3} x + 1 \\

Hope this helps you

4 0
3 years ago
Read 2 more answers
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