#13:
s² = 144
√(s²) = √144
|s| = 12
s = -12 OR s = 12
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#15 (not sure what letter you used so I went with 'g')
(g-6)² = 25
√[(g-6)²] = √25
|g-6| = 5
g - 6 = -5 OR g - 6 = 5
g = 1 OR g = 11
Answer:
Okay, I haven't done this a long time however I believe with this you have to solve the equation by doing substitution.
Step-by-step explanation:
so, if f (x) equals 13, you replace the x in the equation to 13.
f(x)=-2x+5
f(x)=-2(13)+5
f(x)=26+5
f(x)=31
I believe 41 would be your answer. Hope this is right and it helped!
This is a geometric sequence because each term is a constant multiple, called the common ratio, of the previous term. In this case the common ratio, noted as "r", is:
8/-2=-32/8=128/-32=r=-4
The first term is -2
Any geometric sequence can be expressed as:
a(n)=ar^(n-1), a=initial term, r=common ratio, n=term number.
Since we know r and a for this problem already we can say:
a(n)=-2(-4)^(n-1)
Answer:
the answer is C
Step-by-step explanation:
-30m^3-3 here is your answer
